Density = mass/ volume (so here this is how you would solve the problem)
<span>D = 38.6 g/ 2 cm3 (first step)</span>
<span>D= 19.3 g/cm3 ( Do math and then you would get this)</span>
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<span>Hope this helps!! :) </span>
<h2>Hey there! </h2>
<h2>The correct option is:</h2>
<h3>"Government" </h3>
<h2>Explanation:</h2>
<h3>Government is responsible for ruling an authority in a proper way, so the answer is Government. </h3>
<h2>Hope it help you </h2>
Define unit vectors as follows:
is in the eastern direction.
is in the northern direction.
The position of the first bird is
The position of the second bird is
Let θ = the angle between the net displacement vector for the two birds.
By definition,
Similarly,
|b| = 4.025
Therefore
Answer: 36.9°
Answer:
a) P = 1240 lb/ft^2
b) P = 1040 lb/ft^2
c) P = 1270 lb/ft^2
Explanation:
Given:
- P_a = 2216.2 lb/ft^2
- β = 0.00357 R/ft
- g = 32.174 ft/s^2
- T_a = 518.7 R
- R = 1716 ft-lb / slug-R
- γ = 0.07647 lb/ft^3
- h = 14,110 ft
Find:
(a) Determine the pressure at this elevation using the standard atmosphere equation.
(b) Determine the pressure assuming the air has a constant specific weight of 0.07647 lb/ft3.
(c) Determine the pressure if the air is assumed to have a constant temperature of 59 oF.
Solution:
- The standard atmospheric equation is expressed as:
P = P_a* ( 1 - βh/T_a)^(g / R*β)
(g / R*β) = 32.174 / 1716*0.0035 = 5.252
P = 2116.2*(1 - 0.0035*14,110/518.7)^5.252
P = 1240 lb/ft^2
- The air density method which is expressed as:
P = P_a - γ*h
P = 2116.2 - 0.07647*14,110
P = 1040 lb/ft^2
- Using constant temperature ideal gas approximation:
P = P_a* e^ ( -g*h / R*T_a )
P = 2116.2* e^ ( -32.174*14110 / 1716*518.7 )
P = 1270 lb/ft^2
