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finlep [7]
3 years ago
12

How many solutions does this system of equations have?

Mathematics
1 answer:
JulsSmile [24]3 years ago
3 0

Answer:

C. exactly one

Step-by-step explanation:

Hope this is helpful! Happy Halloween!

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Help me with part e please.​
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I believe it would be 98
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draw three rectangles.Then draw to show halves,thirds,and fourths. Write about each whole that you have drawn
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Draw a rectangle, draw a line in middle. This is a halve. 
<span>Draw another rectangle, draw two lines. This is thirds.</span>
<span>Draw another rectangle, draw two lines but in a "+" type of way.. This is fourths.</span>

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2 years ago
On a newly developed IQ test, an individual scores at the 110 level on the first half of the test, and 150 on the second half of
EastWind [94]

Answer:

Reliability

Step-by-step explanation:

The Reliability of a measurement or observation refers to its repeatability. If you measure or observe the same thing twice, how close are the two measurements or observations?

#The test results 110 1nd 150 are between 27% and 36% depending on which direction you take. That variation is wide apart and the test can't be considered reliable.

4 0
3 years ago
The area of a rectangle is 256.5m2. if the length is 18m, what is the perimeter of the rectangle
Vlad [161]
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4 0
2 years ago
Read 2 more answers
For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim
ICE Princess25 [194]

Answer:

Part a) The area of the figure is \frac{9}{2}(4+\pi )\ cm^{2}

Part b) The perimeter of the figure is 3(2+2\sqrt{2}+ \pi)\ cm

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

<u>Find the area of the figure ABC</u>

we have

AB=6\ cm, BC=6\ cm

The area of the half square ABC is equal to find the area of triangle ABC

so

A1=\frac{1}{2}*6*6=18\ cm^{2}

<u>Find the area of the semicircle</u>

The area of the semicircle is equal to

A2=\pi r^{2}/2

we have that

r=6/2=3\ cm

substitute

A2=\pi (3)^{2}/2

A2=(9/2) \pi\ cm^{2}

The area of the figure is equal to

18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

P=AB+AC+length\ CB

we have

AB=6\ cm

Applying Pythagoras theorem

AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm

Remember that

the circumference of a semicircle is equal to

C=\frac{1}{2}2\pi r=\pi r

r=6/2=3\ cm

C=\pi(3)

C=3 \pi\ cm

The perimeter of the figure is equal to

P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm

Simplify

P=3(2+2\sqrt{2}+ \pi)\ cm

5 0
3 years ago
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