∆ABC is isosceles, AB = BC, and CH is an altitude. How long is AC, if CH = 84 cm and m∠HBC = m∠BAC +m∠BCH?
1 answer:
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Answer:
the distance of the Bird (B) from the plane (P) is = 10779 ft
Step-by-step explanation:
From the given information:
a diagrammatic representation is attached below for better understanding and solution to the question.
From the diagram;
Let the Bird (B) be represent as A
The plane (P) be represented by B
The observer be represented by O
and the tower T be represented by C
we will see that:
Also;
AO = BC = 7000
Let consider the trigonometry of triangle BAO
tan θ = opposite/adjacent
tan 33° = 7000/x
0.6494 = 7000/x
x = 7000/0.6494
x = 10779.18
x = 10779 ft ( to the nearest whole number)
Thus; the distance of the Bird (B) from the plane (P) is = 10779 ft
Answer:
x = 35 feet.
Step-by-step explanation:
Given that,
The height of the person is 5 feet.
The height of the flag and the eye is (x-5) feet.
We can calculate using trigonometry.
So, the value of x is equal to 35 feet. The correct option is (c).
