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Oksanka [162]
2 years ago
5

∆ABC is isosceles, AB = BC, and CH is an altitude. How long is AC, if CH = 84 cm and m∠HBC = m∠BAC +m∠BCH?

Mathematics
1 answer:
son4ous [18]2 years ago
3 0
I think I could help you
Have fun and feel free to ask me something new.
Or we can prove some properities without calculating by details

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Kite E F G H is inscribed in a rectangle. Points F and H are midpoints of sides of the rectangle, and creates a side length of x
Hoochie [10]

Answer:

5 units

Step-by-step explanation:

Let point O be the point of intersection of the kite diagonals.

|OF| = 2, |OH| = 5

|FH| = |OF| + |OH| = 2 + 5 = 7

FH and EG are the diagonals of the kite. Hence the area of thee kite is:

Area of kite EFGH = (FH * EG) / 2

Substituting:

35 = (7 * |EG|) / 2

|EG| * 7 = 70

|EG| = 10 units

The longer diagonal of a kite bisects the shorter one, therefore |GO| = |EO| = 10 / 2 = 5 units

x = |GO| = |EO| = 5 units

7 0
3 years ago
Read 2 more answers
Trudy bought 1 foot of fabric. If she cuts the fabric into 3-inch pieces, how many pieces will she have?
WINSTONCH [101]

Answer:

Trudy will have 4 pieces of the fabric.

Step-by-step explanation:

Since, 1 foot of the fabric = 12 inches

If Trudy cuts the fabric into pieces of 3 inch.

Number of pieces she will have = \frac{\text{Total length of the fabric}}{\text{Length of one piece}}

                                                     = \frac{12}{3}

                                                     = 4 pieces

Therefore, she will have 4 pieces of the fabric.

5 0
2 years ago
The difference between two numbers is 15. If 8 is added to twice the greater number, the result is 4 less than 3 times the lesse
yuradex [85]

Answer:


Step-by-step explanation:

Let x be the greater number and y be the smaller number. We know that their difference is 15, so we have

x-y=15

Then, we have the following information: if we add twice the greater (2x) and 8 (2x+8), the result is 3 times the lesser (3y) minus four (3y-4). So, we have

2x+8 = 3y-4 \iff 2x-3y = -12

So, we have the follwing system:

\begin{cases} x-y=15\\2x-3y = -12\end{cases}

From the first equation, we can derive x = y+15, and substitute this expression in the second equation to get

2(y+15)-3y = -12 \iff 2y + 30 -3y = -12 \iff -y = -42 \iff y = 42

Substitute this value for y in the first equation to get

x-42=15 \iff x=15+42 \iff x = 57

8 0
3 years ago
Find the partial fraction of the following ???<br>x/(1-x)³​
Alja [10]

\frac{x}{ {1}^{3} - 3x +  {3x} -  {x}^{3}   }

7 0
3 years ago
The cost per week of running a boarding house is partly constant and partly
patriot [66]

Answer:

the cost of running the boarding

house for 600 students is N61,000

Step-by-step explanation:

Let C represents cost

K1 represents first constant

K2 represents second constant

C= k1+k2n

3500 = k1 + 25 k2............. Eqn(1)

6000= k1 + 50 k2 .............. Eqn(2)

Subtract eqn(1) from eqn(2)

2500= 25k2

K2= 2500/25

K2= 100

To get k1 from eqn(1)

3500 = k1 + 25 k2

Substitute the value of k2

3500 = k1 + 25 (100)

3500= k1 +2500

K1= 3500- 2500

K1= 1000

The equation connecting them;

C= 1000+ 100n

The cost of running the boarding

house for 600 students is

n= 600

C= 1000+ 100(600)

C= 1000+60000

C= N 61,0000

6 0
2 years ago
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