Answer:
87.29%
Step-by-step explanation:
Given: Mean= 68.8 inches
Standard deviation= 2.8 inches
Now, finding the percent of the men in the sample were greater than 72 inches.
We know, z-score=
z-score=
⇒ z-score=
∴ z-score= 1.14
Next, using normal distribution table to find percentage.
Coverting 0.8729 into percentage=
We get the percentage as 87.29%
Hence, 87.29% of the men in the sample were greater than 72 inches.
Answer:
218 students purchased tickets at the dance.
Step-by-step explanation:
Let,
x be the number of presale tickets
y be the number of tickets sold at the dance
According to given statement;
x+y=334 Eqn 1
18x+24y=7320 Eqn 2
Multiplying Eqn 1 by 18
18(x+y=334)
18x+18y=6012 Eqn 3
Subtracting Eqn 3 from Eqn 2
(18x+24y)-(18x+18y)=7320-6012
18x+24y-18x-18y=1308
6y=1308
Therefore,
218 students purchased tickets at the dance.