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2 years ago

How many moles of aluminum are needed to react completely with 4.8 mol of FeO?

1 answer:

6 0

Answer:How many moles of aluminum are needed to react completely with 1.2 mol of FeO? 2Al(s) + 3FeO(s) = 3Fe(s) + Al2O3(s). 0.8 mols.

Explanation:

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When salt is mixed in water, what is the salt and water? A)salt is the solution, water is the solute. B)salt is the solvent, wat

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Answer:

in a solution of salt in water, the solute is salt, and solvent is water.

Explanation:

C) salt is the solute, water is the solvent.

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Plant cells undergo a process called photosynthesis, which uses sunlight to make sugar. Which need does photosynthesis fulfill f

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If you move a substance from one container to another and its volume changes substance is?

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What is Keq for the reaction N₂ + 3H2 = 2NH3 if the equilibrium

hram777 [196]

The Keq for the reaction N₂ + 3H2 = 2NH3 if the equilibrium concentrations are Keq = 1.5. The correct option is D.

Keq is the ratio of the concentration of reactant to the concentration of the product.

The balanced equation is

N₂ + 3H₂ = 2NH₃

The equilibrium constant is $\rm \dfrac{[NH_3]^2}{[N_2]\; [H_2]^3}$

The given concentrations of the compounds have been:

Ammonia = 3 M

Nitrogen = 1 M

Hydrogen = 2 M

$\rm \dfrac{9}{1\times 8} = 1.5$

Thus, the correct option is D. Keq = 1.5.

Learn more about Keq

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2 years ago

Practice Problem: True Stress and Strain A cylindrical specimen of a metal alloy 49.7 mm long and 9.72 mm in diameter is stresse

amm1812

Answer:

The true stress required = 379 MPa

Explanation:

True Stress is the ratio of the internal resistive force to the instantaneous cross-sectional area of the specimen. True Strain is the natural log to the extended length after which load applied to the original length. The cold working stress – strain curve relation is as follows,

σ(t) = K (ε(t))ⁿ, σ(t) is the true stress, ε(t) is the true strain, K is the strength coefficient and n is the strain hardening exponent

True strain is given by

Epsilon t =㏑ (l/l₀)

Substitute㏑(l/l₀) for ε(t)

σ(t) = K(㏑(l/l₀))ⁿ

Given values l₀ = 49.7mm, l =51.7mm , n =0.2 , σ(t) =379Mpa

379 x 10⁶ = K (㏑(51.7/49.7))^0.2

K = 379 x 10⁶/(㏑(51.7/49.7))^0.2

K = 723.48 MPa

Knowing the constant value would be same as the same material is being used in the second test, we can find out the true stress using the above formula replacing the value of the constant.

σ(t) = K(㏑(l/l₀))ⁿ

l₀ = 49.7mm, l = 51.7mm, n = 0.2, K = 723.48Mpa

σ(t) = 723.48 x 106 x (㏑(51.7/49.7))^0.2

σ(t) = 379 MPa

The true stress necessary to plastically elongate the specimen is 379 MPa.

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3 years ago

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