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Alex17521 [72]
3 years ago
11

How much does a gold bar wiegh and how much is it wotrth

Chemistry
1 answer:
Katena32 [7]3 years ago
3 0
It depends on the gold bar.  Gold bars come in all diferent sizes.  However how much its worth depends on how big it is.  Gold is $1,320 per ounce.
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What fraction of a sample of ³H will be left after 36.78 years while undergoing beta decay with a half-life of 12.26 years?​
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Explanation:

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A lake in rural maine drops in ph from 7 to 5 as a result of acid rain falling into it. how has the h+ ion concentration change
Jlenok [28]
The H+ concentration in the lake has increased as a result of the acid rain.
The original pH of the lake was 7, which mean the water is neutral, but due to the acid rain, it drops to 5. This means, that the water has become acidic and how have more hydrogen ion. The H+ concentration in the lake has 100 times compares with its original pH.
3 0
3 years ago
A volume of 90.0 mLmL of aqueous potassium hydroxide (KOHKOH) was titrated against a standard solution of sulfuric acid (H2SO4H2
Alja [10]

Answer:

0.823 M was the molarity of the KOH solution.

Explanation:

H_2SO_4+KOH\rightarrow K_2SO_4+2H_2O (Neutralization reaction)

To calculate the concentration of base , we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=2\\M_1=1.50 M\\V_1=24.7 mL\\n_2=1\\M_2=?\\V_2=90.0 mL

Putting values in above equation, we get:

2\times \1.50 M\times 24.7 mL=1\times M_2\times 90.0 mL

M_2=\frac{2\times 1.50M\times 24.7 mL}{1\times 90.0 mL}=0.823 M

0.823 M was the molarity of the KOH solution.

7 0
3 years ago
this element has an atomic number lower than that of aluminum and one less valence electrons then the Group 16 elements
ahrayia [7]
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Eduardwww [97]
The answer is 19.9 grams cadmium. 
Assuming there was no heat leaked from the system, the heat q lost by cadmium would be equal to the heat gained by the water:
     heat lost by cadmium = heat gained by the water
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Since q is equal to mcΔT, we can now calculate for the mass m of the cadmium sample:
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     mcadmium = 19.9 grams
3 0
3 years ago
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