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horsena [70]
3 years ago
12

Which answer choice best describes why the results of Ernest Rutherford's gold foil experiment led him to propose the concept of

a nucleus? A.) The positively charged alpha particles were deflected more often than expected, which indicated that the gold atoms' negative charges were located at the center of each atom. B.) The positively charged alpha particles were deflected less often than expected, which indicated that the gold atoms' negative charges were not evenly distributed throughout each atom. C.) The positively charged alpha particles were deflected less often than expected, which indicated that the gold atoms' positive charges were located around the outside of each atom. D.) The positively charged alpha particles were deflected more often than expected, which indicated that the gold atoms' positive charges were not evenly distributed throughout each atom.
Chemistry
2 answers:
mixas84 [53]3 years ago
8 0
<h3><u>Answer;</u></h3>

D.) The positively charged alpha particles were deflected more often than expected, which indicated that the gold atoms' positive charges were not evenly distributed throughout each atom.

<h3><u>Explanation</u>;</h3>
  • <em><u>During the experiment, alpha particles bombarded a thin piece of gold foil. The alpha particles were expected to pass easily through the gold foil. Every now and then, however, an alpha particle bounced back- an unexpected result. Rutherford concluded that these particles were striking a tiny region of positive charge.</u></em>
  • The discovery of the nucleus was a result of Rutherford's observation that a small percentage of the positively charged particles bombarding the metal's surface were deflected back towards the source.
  • He concluded that each atom contained a very small, very dense, positively charged center which he called the nucleus.
hammer [34]3 years ago
3 0

Answer:

D

Explanation:

The positively charged alpha particles were deflected more often than expected, which indicated that the gold atoms' positive charges were not evenly distributed throughout each atom.

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Draw the curved arrow mechanism for the addition of HCN in water with NaOH to 3,4-dimethylcyclopentan-1-one to give the correspo
Crank

Answer:

See picture and explanation below

Explanation:

In the attached picture you have the answer for this.

In the first step, we have an acid base reaction between HCN and NaOH. When this happens, its formed the following:

HCN + NaOH --------> CN⁻ + H₂O + Na⁺

As a second step, The CN⁻ attacks the carbonile group in the cyclopentane. This causes to open the double bond, and then, the Cyano enters the molecule.

The final step is another acid base reaction, where the oxygen substracts a hydrogen atom of the water in the medium, and then, the alcohol group is formed. With this step, the cyanohydrin is finally formed. See the mechanism below in the picture.

Hope this helps

6 0
3 years ago
What can you infer about the volume of an object imagined with a greater mass?
pashok25 [27]
We tend to think the greater the mass, the greater the volume but that is not true.  What weighs more a pound of lead or a pound of feathers?  Obviously they are the same however there would be a lot more feathers than lead.  Mass and volume are not really related.
3 0
3 years ago
The larger the molecules of a substance, the the London forces between them. A larger molecule has more electrons and a greater
aev [14]

Answer:

True

Explanation:

All the above statements buttress the fact that the larger molecule, the greater the magnitude of London forces between the molecules. Each of the statements above is a confirmation/explanation of this general rule.

6 0
2 years ago
What type of reaction is required to bind two molecules of glycine together and release a molecule of water?​?
bulgar [2K]
<span>The glycine molecules can bind together and release a molecule of water by the process of condensation. Water would then be considered a by-product of the reaction. Condensation can also be seen when water in the air touches a container filled with cold liquid and you see water drops on the side of the glass.</span>
8 0
2 years ago
Consider an oxygen-concentration cell consisting of two zinc electrodes. One is immersed in a water solution with a low oxygen c
blsea [12.9K]

Answer:

(a) The anode electrode which comprises the zinc electrode being placed in a water solution with low oxygen concentration.

(b) Cathodic reaction is: O_{2} + 2H_{2}O + 4e^{-} ⇒ 4OH^{-}

Anodic reaction is: Zn ⇒Zn^{2+} + 2e^{-}

Explanation:

In the given problem, we have an oxygen-concentration cell consisting of two zinc electrodes. One is immersed in a water solution with a low oxygen concentration and the other in a water solution with a high oxygen concentration. The zinc electrodes are connected by an external copper wire.

(a) Which electrode will corrode?

The electrode that will corrode is the anode electrode which comprises the zinc electrode being placed in a water solution with low oxygen concentration.

(b) Write half-cell reactions for the anodic reaction and the cathodic reaction.

Cathodic reaction is: O_{2} + 2H_{2}O + 4e^{-} ⇒ 4OH^{-}

Anodic reaction is: Zn ⇒Zn^{2+} + 2e^{-}

6 0
3 years ago
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