3 years ago

Calculate the moment of Inertia for a ring with a mass 0.715 kg, an inner radius of 10.7 cm and an outer radius of 12.7 cm.

Physics

1 answer:

lisov135 [29]3 years ago

7 0

Using formula:
I=(1/2)*M*(R^2+r^2)

<span>I=0.5*0.715kg*[(12.7cm)^2+(10.7cm)^2] </span>

<span>I=98.6 kg*cm^2</span>

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