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3 years ago

15

How does the direction of the electric current, moving across a battery powered device, differ from the direction of travel in t

he AC current sent to homes and businesses?

2 answers:

svetoff [14.1K]3 years ago

8 0

They both have different wave traction's

amm18123 years ago

6 0

Different wave tractions

Hope this helps :D

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Where does the shadow of the shuttle in space form?

vekshin1

The shadow forms on the first surface away from the shuttle in the direction opposite the sun.

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3 years ago

18.5 miles per second (30 km/sec). Choose the Earth movement that best relates to this description.

Vladimir79 [104]

Answer:

Earth orbits the SUn

Explanation:

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3 years ago

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True or False: Chemical energy stored in food cannot be transformed into mechanical energy

Novosadov [1.4K]

The answer to this question is false.

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2 years ago

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a net force of 219 N is exterted on a rock. the rock has an acceleration of 3m/s^2 due to this force. what is the mass of the ro

Sonbull [250]

Answer:

<h2>73 kg</h2>

Explanation:

The mass of the object can be found by using the formula

$m = \frac{f}{a} \\$

f is the force

a is the acceleration

From the question we have

$m = \frac{219}{3} \\$

We have the final answer as

<h3>73 kg</h3>

Hope this helps you

6 0

2 years ago

The Moon requires about 1 month (0.08 year) to orbit Earth. Its distance from us is about 400,000 km (0.0027 AU). Use Kepler’s t

dem82 [27]

Answer:

$\frac{M_e}{M_s} = 3.07 \times 10^{-6}$

Explanation:

As per Kepler's III law we know that time period of revolution of satellite or planet is given by the formula

$T = 2\pi \sqrt{\frac{r^3}{GM}}$

now for the time period of moon around the earth we can say

$T_1 = 2\pi\sqrt{\frac{r_1^3}{GM_e}}$

here we know that

$T_1 = 0.08 year$

$r_1 = 0.0027 AU$

$M_e$ = mass of earth

Now if the same formula is used for revolution of Earth around the sun

$T_2 = 2\pi\sqrt{\frac{r_2^3}{GM_s}}$

here we know that

$r_2 = 1 AU$

$T_2 = 1 year$

$M_s$ = mass of Sun

now we have

$\frac{T_2}{T_1} = \sqrt{\frac{r_2^3 M_e}{r_1^3 M_s}}$

$\frac{1}{0.08} = \sqrt{\frac{1 M_e}{(0.0027)^3M_s}}$

$12.5 = \sqrt{(5.08 \times 10^7)\frac{M_e}{M_s}}$

$\frac{M_e}{M_s} = 3.07 \times 10^{-6}$

4 0

3 years ago