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elena-s [515]
3 years ago
11

Which best describes the difference between laser light and regular light

Physics
1 answer:
Grace [21]3 years ago
7 0
Essentially, laser light is a lot of normal light compressed to a point and moving in the same direction
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The force between two moving objects that are touching
Jet001 [13]
This is unclear. What are the objects? Is it a balloon? A rubber ball?
6 0
4 years ago
Read 2 more answers
Expand (2x + y) (2x - y).​
KiRa [710]

Answer: 4x²-y²

Explanation:

FORMULA

a²-b²=(a+b)(a-b)

-----------------------------

(a+b)(a-b)=a²-b²

(2x+y)(2x-y)=(2x)²-(y)²

                  =4x²-y²

Hope this helps!! :)

Please let me know if you have any question

8 0
3 years ago
un cilindro uniforme empujado por una tabla desde una posicion inicial mostrada en la figura, rueda hacia delante por el suelo,
Andreyy89

Answer:

L/2.

Explanation:

Hola.

En este caso, dado que el hombre empuja el cilindro desde el punto L=0 y hasta la mitad de la longitud entre el hombre y el cilindro, es claro que el cilindro se desplaza un L/2 más de la distancia inicial entre el hombre y el cilindro, de este modo, inferimos que el hombre también ha caminado L/2.

¡Saludos!

5 0
4 years ago
When talking about Acceleration ,what is significant about the about the sign(+ or -)?​
OLEGan [10]

Answer:

Acceleration at its most basic is the act of increasing your running speed. From a standing start (or blocks), you explode into action. If you’re already running, you pick up the pace. Acceleration continues until you can no longer increase your speed, at which point you achieve maximum velocity (top-end speed). Acceleration seems simple enough. The plus means your increasing speed, the k=minus means your decreasing in speed.

Explanation:

5 0
3 years ago
An unwary football player collides with a padded goalpost while running at a velocity of 7.50 m/s and comes to a full stop after
mr Goodwill [35]

Answer:

(a) 80.36 m/s^2

(b)  0.0933 second

Explanation:

initial velocity, u = 7.5 m/s

final velocity, v = 0 m/s

distance moved, s = 0.350 m

(a) Let a be the deceleration.

Use third equation of motion

v^{2}=u^{2}+2\times a\times s

0^{2}=7.5^{2}+2\times a\times 0.350

a = 80.36 m/s^2

Thus, the deceleration is 80.36 m/s^2.

(b) Let the time taken is t

Use first equation of motion

v = u + a t

0 = 7.5 + 80.36 x t

t = 0.0933 second

7 0
3 years ago
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