A bike and rider together have a mass of 60 kg. If the bike and rider have an acceleration of 2.0 m/s^2, what is the force on th
1 answer:
The net force on the bike and the rider is 120 N
Explanation:
We can solve this problem by applying Newton's second law of motion, which states that:
F = ma
where
F is the net force exerted on an object
m is the mass of the object
a is its acceleration
For the bike and the rider in this problem, we have
m = 60 kg is their combined mass
is their acceleration
Therefore, the net force on them is
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Answer:
mu = 0.56
Explanation:
The friction force is calculated by taking into account the deceleration of the car in 25m. This can be calculated by using the following formula:
v: final speed = 0m/s (the car stops)
v_o: initial speed in the interval of interest = 60km/h
= 60(1000m)/(3600s) = 16.66m/s
x: distance = 25m
BY doing a the subject of the formula and replace the values of v, v_o and x you obtain:
with this value of a you calculate the friction force that makes this deceleration over the car. By using the Newton second's Law you obtain:
Furthermore, you use the relation between the friction force and the friction coefficient:
hence, the friction coefficient is 0.56