1) The minute travels the circumference of a 4 inches circle is 60 minutes:
Circumference = 2πr = 2π(2in) = 4π in
Time = 60 minutes
2) Constant angular velocity => (4π / 60) = (x / 20) => x = 4π / 3 inches
x = 4.19 inches
Answer: 4.19 inches
Answer:
C_{y} = 4.96 and θ' = 104,5º
Explanation:
To add several vectors we can decompose each one of them, perform the sum on each axis, to find the components of the resultant and then find the module and direction.
Let's start by decomposing the two vectors.
Vector A
sin θ =
/ A
cos θ = Aₓ / A
A_{y} = A sin θ
Ax = A cos θ
A_{y} = 4.9 sin 31 = 2.52
Ax = 4.9 cos 31 = 4.20
Vector B
B_{y} = B sin θ
Bx = B cos θ
B_{y} = 6 sin 156 = 2.44
Bx = 6 cos 156 = -5.48
The components of the resulting vector are
X axis
Cx = Ax + B x
Cx = 4.20 -5.48
Cx = -1.28
Axis y
C_{y} = Ay + By
C_{y} = 2.52 + 2.44
C_{y} = 4.96
Let's use the Pythagorean theorem to find modulo
C = √ (Cₙ²x2 + Cy2)
C = Ra (1.28 2 + 4.96 2)
C = 5.12
We use trigonemetry to find the angle
tan θ = C_{y} / Cₓ
θ’ = tan⁻¹ (4.96 / (1.28))
θ’ = 75.5
como el valor de Cy es positivo y Cx es negativo el angulo este en el segundo cuadrante, por lo cual el angulo medido respecto de eje x positivo es
θ’ = 180 – tes
θ‘= 180 – 75,5
θ' = 104,5º
<span>What you need to do while answering this questions, is ask yourself what has cells - only if a thing has cells can you see those cells under a microscope. Objects of animal and plant origin have cells, so blood, plant and cork (made of tree bark) can have cells, and a box too, if it's made of wood. So we can''t exclude any answers based on this. We must then know the story of Robert Hook - and it was in fact a cork. He did this discovery around 1655. At the time his main interest was the microscope rather than the cork, and he used to cork to demonstrate the function of the microscope. The correct answer is CORK.</span>
Responder:
35,2 ohm.
Explicación:
Dado:
La resistencia específica del conductor es,
La longitud del conductor es,
El área de la sección transversal del conductor es,
Sabemos que la resistencia de un conductor es directamente proporcional a su longitud e inversamente proporcional al área de la sección transversal.
Por lo tanto, la resistencia se puede expresar como:
![R=\frac{\rho\times l}{A}](https://tex.z-dn.net/?f=R%3D%5Cfrac%7B%5Crho%5Ctimes%20l%7D%7BA%7D)
Ahora, conecte los valores dados y resuelva para 'R'. Esto da,
![R=\frac{1.6\times 10^{-6}\ ohm\cdot m\times 110\ m}{5\times 10^{-6}\ m^2}\\\\R=35.2\ ohm](https://tex.z-dn.net/?f=R%3D%5Cfrac%7B1.6%5Ctimes%2010%5E%7B-6%7D%5C%20ohm%5Ccdot%20m%5Ctimes%20110%5C%20m%7D%7B5%5Ctimes%2010%5E%7B-6%7D%5C%20m%5E2%7D%5C%5C%5C%5CR%3D35.2%5C%20ohm)
Por lo tanto, la resistencia del conductor es de 35,2 ohm.
Answer:
200 kgm/s
Explanation:
momentum = mass x velocity