Well let see, we don't have any information about the initial distance we have to use our logic
assuming that the distance moves from 1 to 2 m with initial speed , it means that the distance factor is 2
Since the initial speed has doubled, it would be very likely that the factor of the distance is MORE THAN 2 . Find the answer that either got 3 or 4 distance factor
hope this helps
Explanation:
Given that,
Radius in which the satellite orbits, r = 6588 km
Solution,
The centripetal force acting on the satellite is balanced by the gravitational force acting between earth and the satellite. Its expression can be written by :
, M is the mass of earth
v = 7782.53 m/s
Let t is the time required to complete one orbit. It can be calculated as :
t = 5318.78 seconds
or
t = 1.47 hour
Therefore, this is the required solution.
Answer:
magnification = - 30
overall magnification = -240
Explanation:
given data
Focal length of microscope objective f = 0.150 cm
Object distance from microscope objective do = 0.155 cm
magnification by eyepiece = 8 ×
to find out
What magnification is produced and overall magnification
solution
we consider here Image distance from microscope objective is = di
so that
Magnification produced by objective will be = -
so we find here di by given equation that is
..................1
di = 4.65 cm
so that magnification by object will be
magnification = -
magnification = -
magnification = - 30
and
overall magnification will be
overall magnification = magnification by objective × magnification by eyepiece ........................2
overall magnification = -30 × 8
overall magnification = -240
graphic too wide.
indep variable is one you control
dep var is what happens