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jolli1 [7]
3 years ago
14

A kayak on a lake is moving at a constant speed of 2.4 m/s in a direction 41.2° north of west. After 27 min, find the following.

Physics
1 answer:
xeze [42]3 years ago
5 0

Answer:

b

Explanation:

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The place you get your hair cut has two nearly parallel mirrors 6.5 m apart. As you sit in the chair, your head is
Ghella [55]

Complete question is;

The place you get your hair cut has two nearly parallel mirrors 6.50 m apart. As you sit in the chair, your head is 3.00 m from the nearer mirror. Looking toward this mirror, you first see your face and then, farther away, the back of your head. (The mirrors need to be slightly nonparallel for you to be able to see the back of your head, but you can treat them as parallel in this problem.) How far away does the back of your head appear to be?

Answer:

13 m

Explanation:

We are given;

Distance between two nearly parallel mirrors; d = 6.5 m

Distance between the face and the nearer mirror; x = 3 m

Thus, the distance between the back-head and the mirror = 6.5 - 3 = 3.5m

Now, From the given values above and using the law of reflection, we can find the distance of the first reflection of the back of the head of the person in the rear mirror.

Thus;

Distance of the first reflection of the back of the head in the rear mirror from the object head is;

y' = 2y

y' = 2 × 3.5

y' = 7

The total distance of this image from the front mirror would be calculated as;

z = y' + x

z = 7 + 3

z = 10

Finally, the second reflection of this image will be 10 meters inside in the front mirror.

Thus, the total distance of the image of the back of the head in the front mirror from the person will be:

T.D = x + z

T.D = 3 + 10

T.D = 13m

8 0
3 years ago
A 120 N force, directed at an angle θ above a horizontal floor, is applied to a 28.0 kg chair sitting on the floor. If θ = 0°, w
ivanzaharov [21]

Answer:

See explanation

Explanation:

Given:-

- The applied force Fa = 120 N

- The angle made with Fa and horizontal =  θ

- The mass of chair m = 28.0 kg

Find:-

a) θ = 0 ,  the horizontal component Fh of the applied force and (b) the magnitude FN of the normal force of the floor on the chair?

If θ = 34.0°, what are (c)Fh and (d)FN?

If θ = 65.0°, what are (e)Fh and (f)FN?

Now assume that the coefficient of static friction between chair and floor is 0.410. What is the maximum force of static friction on the chair if θ is (g) 0°, (h)34.0°, and (i)65.0°?

Solution:-

- We will consider the applied force (Fa) and develop a general expression for Fh as function of θ. Using Trigonometry we have:

                                     Fh = Fa*cos ( θ )

- The normal contact force (N) can be expressed similarly by applying equilibrium conditions on the chair in vertical direction.

                                    N - mg - Fa*sin(θ) = 0

                                    N = m*g + Fa*sin(θ)  

For, θ = 0:

                                    Fh = Fa*cos(0) = Fa

                                    Fh = 120 N

                                    N = (28*9.81) + 120*0

                                    N = 274.68 N

For, θ = 34.0:

                                    Fh = Fa*cos(34) = (120)*(0.82903)

                                    Fh = 99.5 N

                                    N = (28*9.81) + 120*sin(34)

                                    N = 341.8 N

For, θ = 65.0:

                                    Fh = Fa*cos(65) = (120)*(0.42261)

                                    Fh = 50.7 N

                                    N = (28*9.81) + 120*sin(65)

                                    N = 383.4 N

- The maximum frictional force (Ff) is given by the following expression:

                                   Ff = N*us

Where,                        us = coefficient of static friction = 0.41

For, θ = 0:

                                   Ff = (274.68)*(0.41)

                                   Ff = 112.62 N

For, θ = 34:

                                   Ff = (341.8)*(0.41)

                                   Ff = 140.13 N

For, θ = 65:

                                   Ff = (383.4)*(0.41)

                                   Ff = 157.2 N

5 0
3 years ago
A baseball bat exerts an average force of 600. newtons east on a ball, imparting an impulse of
Anvisha [2.4K]

Answer: The time of contact will be 0.006 seconds.

Explanation:

An impulse of a force is the product of average force and the time interval when the force acts.

Mathematically,

J=F\Delta t

Where,

J = impulse = 3.6 Ns

F = Force = 600N

\Delta t = Time = ?s

Putting the values in above equation, we get:

3.6Ns=600N\times t

t = 0.006 seconds

Hence, the time of contact will be 0.006 seconds.

3 0
3 years ago
Read 2 more answers
What is an ion found in a glass of water
stepladder [879]

Answer:

H^{+} ion and OH^{-} ions.

Explanation:

As we notice the glass of water, in this observation we find that the glass also made up of sodium silicate which will give us oxygen ion.

And the water which is present in the glass will break into the hydroxyl ion and H^{+} ion .

Therefore, glass of water contains H^{+} ion and OH^{-} ions.

3 0
4 years ago
a mass is measured as 6.2kg in one experiment and as 6.20kg in another. in what way do these two measurements differ?
Lubov Fominskaja [6]

Answer:

They do not differ because 6.2 is the same as 6.20

Explanation:

8 0
3 years ago
Read 2 more answers
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