Let's say a = number of ordered soups, b = number of ordered sandwiches.
Then 4.5a + 7.75b = 113.50, and a and b are integers between 0 and 18 inclusive.
How do we tackle this? If all ordered soup, the cost would be $81, so we'll have at least 4 sandwiches. If all ordered sandwich, the cost would be $139.5, so at most 15 sandwiches were ordered. You also know an even number of sandwiches was ordered, to let the price end at 50 cent.
If you brute-force from 4,6,8,10,12 to 14 sandwiches, you find the answer at 10 sandwiches and 8 soups.
10*7.75 + 8*4.50 = 113.50
I think you mean length times width, which is more simply written as lw.
Answer:
1.)4188.79
2.) 7238.23
3.)1.02
4.)4189
5.)170 cm³
Step-by-step explanation:
1.) 4πr2 * 5
2.) 4πr2 * 12
3.) V = 4/3(PI*r3). *4.5
4.) V = 4/3 π r ^3 * 10
5.) Given:
Cylindrical container: height = 18 cm ; diameter = 6 cm.
3 balls each have a radius of 3 cm.
Volume of a cylinder = π r² h
V = 3.14 * (3cm)² * 18 cm
V = 508.68 cm³
Volume of rubber ball = 4/3 π r³
V = 4/3 * 3.14 * (3cm)³
V = 113.04 cm³
113.04 cm³ * 3 balls = 339.12 cm³
508.68 cm³ - 339.12 cm³ = 169.56 cm³ or 170 cm³
There is 170 cm³ free space in the container.
Answer:
see attached
Step-by-step explanation:
3x(x − 2)(5x + 2)
- (x − 2)(5x + 2) expand
- 5x² - 8x - 4
- 3x ( 5x² - 8x - 4) expand
- 15x³ - 24x² - 12x
Answer:
C (reflection across the x access)
Step-by-step explanation:
I got it right on edge
