How much energy is required to raise the temperature of 74 g of water from 19 °C to 47 °C.
1 answer:
Answer:
The energy required is 8660.96 J.
Explanation:
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heat is the amount of heat that a body absorbs or releases without any changes in its physical state (phase change). This heat is given by the expression:
Q = c * m * ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
In this case, you know:
- C= 4.18
- m= 74 g
- ΔT= Tfinal - Tinitial= 47 C - 19 C= 28 C
Replacing:
Q= 4.18 *74 g* 28 C
Solving:
Q= 8660.96 J
<u><em>The energy required is 8660.96 J.</em></u>
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