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Ulleksa [173]
3 years ago
14

Find the slope of the line that passes through M(-6, 2) and N(-4, -2)

Mathematics
1 answer:
Yuliya22 [10]3 years ago
6 0

Answer:

y=-2x-14

Step-by-step explanation:

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What is the answer and how to do this?​
zhenek [66]

Answer:

<u>a</u>

Step-by-step explanation:

Given :

⇒ P (Sumit) = 1/2

⇒ P (Sujan) = 1/3

⇒ P (Rakesh) = 1/a

⇒ P (total) = 3/4

============================================================

Solving :

⇒ 1/2 × 1/3 × 1/a = 3/4

⇒ 1/6 × 1/a = 3/4

⇒ 2/12 × 1/a = 9/12

⇒ a = <u>9/2</u>

6 0
2 years ago
A certain company assigns employees to offices in such a way that some of the offices can be empty and more than one employee ca
vladimir2022 [97]

Answer:

There are 8 ways.

Step-by-step explanation:

For each employee there are two possibilities: first office and second office.

Therefore,

the number of ways the company can assign 3 employees to 2 different offices will be :  

2^{3} = 8

We can also look at this problem like suppose ABC are employees.

We can arrange them like -

0 ABC

ABC 0

AB C

BC A

CA B

A BC

B CA

C AB

So, there are total 8 WAYS.

4 0
3 years ago
PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!!!!!!!!!!!!!!!!!!!PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!
Semenov [28]

Answer:

1/20

Alternate from 0.05, 20 - 1

Hope this helps

7 0
3 years ago
Read 2 more answers
Simplify.<br><br><br> (1/2)^2−6(2−2/3)
Elena L [17]

Answer:

Exact form : -31/4

Decimal form: -7.75

mixed number form: -7(3/4)

Step-by-step explanation:

7 0
3 years ago
A manufacturer produces piston rings for an automobile engine. It is known that ring diameter is normally distributed with σ=0.0
oksian1 [2.3K]
<h2>Answer with explanation:</h2>

The confidence interval for population mean is given by :-

\overline{x}\pm z^* SE                   (1)

, where \overline{x} = sample mean

z* = critical value.

SE = standard error

and SE=\dfrac{\sigma}{\sqrt{n}} , \sigma = population standard deviation.

n= sample size.

As per given , we have

\overline{x}=74.021

\sigma=0.001

n= 15

It is known that ring diameter is normally distributed.

SE=\dfrac{0.001}{\sqrt{15}}=0.000258198889747\approx0.000258199

By z-table ,

The critical value for 95% confidence  = z*= 1.96

A 99% two-sided confidence interval on the true mean piston diameter :

74.021\pm (2.576) (0.000258199)     (using (1))

74.021\pm 0.000665120624

74.021\pm 0.000665120624\\\\=(74.021- 0.000665120624,\ 74.021+ 0.000665120624)\\\\=(74.0203348794,\ 74.0216651206)\approx(74.020,\ 74.022)  [Rounded to three decimal places]

∴  A 99% two-sided confidence interval on the true mean piston diameter  = (74.020, 74.022)

By z-table ,

The critical value for 95% confidence  = z*= 1.96

A 95% lower confidence bound on the true mean piston diameter:

74.021- (1.96) (0.000258199)    (using (1))

74.021- 0.00050607004=74.02049393\approx74.020 [Rounded to three decimal places]

∴  A 95% lower confidence bound on the true mean piston diameter= 74.020

7 0
3 years ago
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