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4 years ago

Which type of polymer is RNA?

Chemistry

2 answers:

motikmotik4 years ago

6 0

Answer: The correct answer is a nucleic acid.

Explanation:

Full form of RNA is ribonucleic acid. It is a nucleic acid which is present in all the living cells.

The role of RNA is basically to act as a messenger which carries instructions from DNA to control the synthesis of proteins.

It is a polymer of nucleic acid. There are 4 nucleic acids which combine to form RNA. The four nucleic acids are: Adenine (A), Guanine (G), Uracil (U) and Cytosine (C).

Adenine bonds with Uracil and Guanine bonds with Cytosine.

Hence, the correct answer is a nucleic acid.

Alex787 [66]4 years ago

5 0

a nucleic acid
Explanation: The nucleic acids, both DNA and RNA, consist of polymers ofnucleotides. The nucleotides are linked covalently between the 3' carbon atom of the pentose and thephosphate group attached to the 5' carbon of the adjacent pentose

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At a certain temperature, 0.900 mol SO 3 is placed in a 2.00 L container. 2 SO 3 ( g ) − ⇀ ↽ − 2 SO 2 ( g ) + O 2 ( g ) At equil

puteri [66]

Answer: The value of $K_c$ is 0.0057

Explanation:

Initial moles of $SO_3$ = 0.900 mole

Volume of container = 2.00 L

Initial concentration of $SO_3=\frac{moles}{volume}=\frac{0.900moles}{2.00L}=0.450M$

equilibrium concentration of $O_2=\frac{moles}{volume}=\frac{0.110mole}{2.00L}=0.055M$ [/tex]

The given balanced equilibrium reaction is,

$2SO_3(g)\rightleftharpoons 2SO_2(g)+O_2(g)$

Initial conc. 0.450 M 0 0

At eqm. conc. (0.450 -2x) M (2x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[O_2][SO_2]^2}{[SO_3]^2}$

$K_c=\frac{x\times (2x)^2}{0.450-2x)^2}$

we are given : x = 0.055

Now put all the given values in this expression, we get :

$K_c=\frac{0.055\times (2\times 0.055)^2}{0.450-2\times 0.055)^2}$

$K_c=0.0057$

Thus the value of the equilibrium constant is 0.0057

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4 years ago

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