Reactant C is the limiting reactant in this scenario.
Explanation:
The reactant in the balanced chemical reaction which gives the smaller amount or moles of product is the limiting reagent.
Balanced chemical reaction is:
A + 2B + 3C → 2D + E
number of moles
A = 0.50 mole
B = 0.60 moles
C = 0.90 moles
Taking A as the reactant
1 mole of A reacted to form 2 moles of D
0.50 moles of A will produce 
= 
thus 0.50 moles of A will produce 1 mole of D
Taking B as the reactant
2 moles of B reacted to form 2 moles of D
0.60 moles of B reacted to form x moles of D
= 
x = 2 moles of D is produced.
Taking C as the reactant:
3 moles of C reacted to form 2 moles of D
O.9 moles of C reacted to form x moles of D
= 
= 0.60 moles of D is formed.
Thus C is the limiting reagent in the given reaction as it produces smallest mass of product.
Answer:
High concentration of glutathione should be included in the elution buffer for the given experiment to remove protein from the column.
Explanation:
Affinity chromatography is one of important biochemical technique of chromatography which depends on the affinity of ligand for the receptor.Here the ligand is a protein mixture which act as mobile phase and the receptor is present in the wall of chromatography column act as stationary phase.When the protein mixture is applied on the top of the column the substances present within the protein that have high affinity for the receptor present in the walls of chromatography column binds to the later but rest of the protein pass away through the column.High concentration of ligand is used within an buffer solution to remove the desired protein from the column.
From this point of view it can be stated that in the given question high concentration of glutathione should be used to remove the desired protein from the column.
Answer:
17,932.69 g/mol is the molecular weight of the substance.
Explanation:
Using Beer-Lambert's law :
Formula used :
where,
A = absorbance of solution = 1.04
c = concentration of solution =?
l = length of the cell = 1 cm
= molar absorptivity of this solution = 18,650 
Now put all the given values in the above formula, we get the molar absorptivity of this solution.
c = 
V = Volume of the solution in L
Molecular weight of the substance = x
V = 100 mL = 0.1 L
Mass of the substance = 100 mg = 0.1 g
x = 17,932.69 g/mol
17,932.69 g/mol is the molecular weight of the substance.
Percentage
by mass is the amount in mass of a component in a mixture per 100 unit of mass of the total
mixture. Percentage by mass is the same as %w/w. In order to determine this value, we need to know the mass of the substance in question and the total mass of the sample. In this case, we have to know the mass of Fe by doing certain calculations. Then, we divide this value by the total mass given of the ore, 4.05 g and multiply by 100%. It should be expressed as follows:
Percent by mass = mass of Fe in ore / 4.05 g ore sample x 100
However, the question is lacking some information so we cannot really specify the answer.
