Step-by-step explanation:
This is what the triangle should look like, when you draw it.
As its a right-angle triangle, trigonometry was used.
Let theta represent the angle of cosine C
What is the equation of the two points 3,5 and 5,0
1 answer:
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Answer: ;
Step-by-step explanation:
You can write two expressions that are in terms of 'x' and 'y'. This is a right triangle, so Pythagorean's theorem can be used. We can also use the angle to find the sine of 30 degrees.
<u>Pythagorean's Theorem:</u>
The values 'a' and 'b' are the two shorter sides of the triangle, while the value 'c' is the longest side of the triangle; the hypotenuse.
<u>Sine of the Angle:</u>
Sine is defined to be the opposite side divided by the hypotenuse. Let's take the sine of 30 degrees:
Plug this value of 'y' into the first expression derived from Pythagorean's theorem:
Use this value of 'x' to solve for 'y' in the expression from Pythagorean's theorem:
Answer:
y = -x - 6
Step-by-step explanation:
If we are looking for the equation of the line tangent to the circle, we have to find the first derivative of the circle function. If that tangent line is to be parallel to the given tangent line, we need to find the slope of the the given tangent line and make sure the slope of the line we are looking for is the same. First let's find the slope of the given tangent. If the given tangent is x+y=6, then to find the slope, solve for y:
y = -x + 6. So the slope of that line, and also the slope of the tangent we are solving for, is -1. Hold that thought while we find the derivative of the function. Using implicit differentiation, we find the derivative to be:
Solving for the slope (dy/dx) gives us:
and
so
Subbing in the value of the slope we found:
so
-y = -x or, equivalently,
y = x. Now that we know that y and x are the same value, we can go back to the original circle to find out what they both are by substitution. If y = x, we make the substution:
If , then
and
and
so
y = ±3
We will choose the negative root (you'll see why in a second) and sub that in for both y and x since y and x are th same number. Going back to the fact that the slope is -1:
y - (-3) = -1(x - (-3)) simplifies a bit to:
y + 3 = -x - 3 which gives us, in slope-intercept form:
y = -x - 6
That is the equation of the tangent to the circle that is parallel to the given tangent.
If we would have chosen the principle (or positive) root of 3, our equation would have looked like this:
y - 3 = -1(x - 3) and
y = -x + 3 + 3 so
y = -x + 6. Notice that that is the EXACT SAME EQUATION as the given tangent. That's why we have to pick the negative 3 as our root.
Good luck in your calculus class! Make sure you post your questions in here! Many of us LOVE the challenge of calculus!