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Nookie1986 [14]
3 years ago
8

Hi guys, can someone please help with this assignment :

Mathematics
1 answer:
mina [271]3 years ago
6 0

If there is no real solution the Discriminant (b^2 - 4ac) will have a value less than zero.  The a, b and c refer to the coefficients in the equation

ax^2 + bx + c = 0.

So for this equation  to have no real solution 4^2 - 4*p * 6 < 0

-24p + 16 < 0

-24p < -16

p > 16/24

p > 2/3

So the value of p must be greater than 2/3 for no real solutions,  (answer).

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Nana76 [90]
The answer is 6. 49 you welcome :)
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3 years ago
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Can anyone please help with this problem ASAP ?
lara31 [8.8K]

Answer:

4 would be $55.00 and 8 would be $75.00

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2 years ago
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Find k, the constant of proportionality, for the data in this table. Then write an equation for the relationship.
VashaNatasha [74]

Answer:

k=\frac{32}{5},  y=\frac{32}{5}x

k=6.4, y=6.4x

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form k=\frac{y}{x} or y=kx

Find the value of the constant of proportionality k

take any ordered pair from the data

For x=25, y=160

k=\frac{y}{x}

substitute the values of x and y

k=\frac{160}{25}

simplify

k=\frac{32}{5}

The linear equation is equal to

y=\frac{32}{5}x

or

y=6.4x

7 0
3 years ago
A car insurance company has high-risk, medium-risk, and low-risk clients, who have, respectively, probabilities .04, .02, and .0
Paha777 [63]

Answer:

(a) 0.983

(b) 0.353 or 35.3%

(c) 0.604 or 60.4%

Step-by-step explanation:

a) The probability of a random client does not file a claim is equal to the sum of:

1) the probability of a client being high risk and does not file a claim = P(hr)*(1-P(c_hr))

2) the probability of a client being medium risk and does not file a claim = P(mr)*(1-P(c_mr))

and

3) the probability of a client being low risk and does not file a claim = P(lr)*(1-P(c_lr))

P(not claim) = P(hr)*(1-P(c_hr))+P(mr)*(1-P(c_mr))+P(lr)*(1-P(c_lr))

P(not claim) = 0.15*(1-0.04)+0.25*(1-0.02)+0.6*(1-0.01)

P(not claim) = 0.15*0.96+0.25*0.98+0.6*0.99 = 0.983

(b) To know the proportion of claims that come from high risk clients we need to know the total expected claims in every category:

Claims expected by high risk clients = P(c_hr)*P(hr) = 0.04*0.15 = 0.006 claims/client

Claims expected by medium risk clients = P(c_mr)*P(mr) = 0.02*0.25 = 0.005 claims/client

Claims expected by low risk clients = P(c_lr)*P(lr) = 0.01*0.60 = 0.006 claims/client

The proportion of claims done by high risk clients is

Claims by HR clients / Total claims expected = 0.006 / (0.006+0.005+0.006) =  0.006 / 0.017 = 0.3529 or 35,3%

(c)  The probability of being a client of a particular category and who don't file a claim is:

1) High risk: 0.15*(1-0.04) = 0.144

2) Medium risk: 0.25*(1-0.02) =  0.245

3) Low risk: 0.6*(1-0.01) = 0.594

The probability that a random client who didn't file a claim is low- risk can be calculated as:

Probability of being low risk and don't file a claim / Probability of not filing a claim

P(LR&not claim)/P(not claim) = 0.594 / (0.144+0.245+0.594)

P(LR&not claim)/P(not claim) = 0.594 /  0.983 = 0.604 or 60.4%

6 0
3 years ago
Which equation is represented by the table?
kozerog [31]
(0,-1)(1,4)
slope = (4 - (-1) / (1 - 0) = (4 + 1)/1 = 5

y = mx + b
slope(m) = 5
(1,4)...x = 1 and y = 4
now we sub
4 = 5(1) + b
4 = 5 + b
4 - 5 = b
-1 = b

equation is : y = 5x - 1...answer C
6 0
3 years ago
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