Answer:
2. A force of 50 N is applied to the object for a distance of 2.0 m. Assume that object(the mass of the object is 3kg)
was at rest at the beginning, what speed did it achieved because of the work done on it? (Hint:
Calculate the works performed by the force first.)
I figured that is 8.2m/S,I am just not sure can anyone help me i much appreciate it.
Answer:
the neutron star becomes a black hole
True is the answer. I believe
Answer:
P = 7.28 N.s
Explanation:
given,
initial momentum of cue ball in x- direction,P₁ = 9 N.s
momentum of nine ball in x- direction, P₂ = 2 N.s
momentum in perpendicular direction i.e. y - direction,P'₂ = 2 N.s
momentum of the cue after collision = ?
using conservation of momentum
in x- direction
P₁ + p = x + P₂
p is the initial momentum of the nine balls which is equal to zero.
9 + 0 = x + 2
x = 7 N.s
momentum in x-direction.
equating along y-direction
P'₁ + p = y + P'₂
0 + 0 = y + 2
y = -2 N.s
the momentum of the cue ball after collision is equal to resultant of the momentum .


P = 7.28 N.s
the momentum of the cue ball after collision is equal to P = 7.28 N.s
Answer:
(a). The net gravitational force is 
(b). The position is at 0.232 m.
Explanation:
Given that,
Mass of one object M = 255 kg
Mass of another object M'= 555 kg
Separation = 0.390 m
(a). We need to calculate the net gravitational force
Using formula of force


Put the value into the formula


The net gravitational force is 
(b). We need to calculate the position
Force from 555 mass = Force from 255 mass




The position is at 0.232 m.
Hence, (a). The net gravitational force is 
(b). The position is at 0.232 m.