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KIM [24]
4 years ago
5

The burning rates of two different solid-fuel propellants used in aircrew escape systems are being studied. It is known that bot

h propellants have the same standard deviation of burning rate; σ1 = σ2 = 3 centimetres per second. Two random samples of n1 = n2 = 20 are tested; the sample mean burning rates are 23.7 and 24 centimetres per second respectively. If you want to test the hypothesis that the burning rates of the 2 propellants are different, what is the value of zcalc? In computing zcalc, use the hypothesis test with respect to LaTeX: \mu1-\mu2 μ 1 − μ 2 . Please report your answer in 2 decimal places.
Physics
1 answer:
Katena32 [7]4 years ago
5 0

Answer: z_{\text{calc}}=-0.32

Explanation:

The test statistic for difference of two population means :-

z=\dfrac{\mu_1-\mu_2}{\sigma\sqrt{\dfrac{1}{n_1}+\dfrac{1}{n_2}}}

Given : \sigma=\sigma_1=\sigma_2=3

n_1 = n_2 = 20

\mu_1=23.7

\mu_2=24

Then , z=\dfrac{23.7-24}{(3)\sqrt{\dfrac{1}{20}+\dfrac{1}{20}}}

\Rightarrow\ z=-0.316227766017\approx-0.32

Hence, the value of z_{\text{calc}}=-0.32

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What two things keeps the planets, asteroids, comets and moons in orbit?
gregori [183]
Answer:

The sun's gravity pulls the planet toward the sun, which changes the straight line of direction into a curve. This keeps the planet moving in an orbit around the sun. Because of the sun's gravitational pull, all the planets in our solar system orbit around it.
5 0
3 years ago
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A hockey puck with a mass of 0.175 kg slides over the ice. The puck initially slides with a speed of 5.25 m/s, but it comes to a
Neko [114]

Answer:

1.70 J

Explanation:

The heat dissipated is the difference in the kinetic energies.

This is given by

E = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2

v_i and v_f are the initial and final velocities.

With <em>m</em> = 0.175 kg,

E = \frac{1}{2}\times0.175(2.85^2 - 5.25^2) = -1.701\text{ J}

The negative sign appears because energy is lost.

7 0
3 years ago
as an aid in understanding this problem. The drawing shows a positively charged particle entering a 0.61-T magnetic field. The p
miv72 [106K]

Answer:

E = 420.9 N/C

Explanation:

According to the given condition:

Net\ Force = 2(Magnetic\ Force)\\Electric\ Force - Magnetic\ Force = 2(Magnetic\ Force)\\Electric\ Force = 3(Magnetic\ Force)\\qE = 3qvBSin\theta\\E = 3vBSin\theta

where,

E = Magnitude of Electric Field = ?

v = speed of charge = 230 m/s

B = Magnitude of Magnetic Field = 0.61 T

θ = Angle between speed and magnetic field = 90°

Therefore,

E = (3)(230\ m/s)(0.61\ T)Sin90^o

<u>E = 420.9 N/C</u>

3 0
3 years ago
if you went to the doctor 3 weeks ago &amp;&amp; youre going back, will they have to measure your height and weigh you again?
tino4ka555 [31]
No, they usually will not. It also depends why you're going/why you went the first time.
5 0
3 years ago
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A room has a volume of 160 m3. An air-conditioning system is to replace the air in this room every 21.3 minutes, using ducts tha
serious [3.7K]

Answer:

A. 0.204203928 m

b. 0.1443939822

Explanation:

Givens:

Volume (V) = 160 m^3

velocity 1 (v1) = 3.00 m/s

velocity 2 (v2) = 6.00 m/s

Time (t) = 21.3 minutes = 1278 seconds

Side length = ?

V = A*v*t

A = s^2

V = s^2*v*t

s= \sqrt{\frac{V}{v*t} }

A.

s = \sqrt{\frac{V}{v*t} } = \sqrt{\frac{160}{3.00*1278} } = 0.204203928 m

B.

s = \sqrt{\frac{V}{v*t} } = \sqrt{\frac{160}{6.00*1278} } = 0.1443939822 m

I hope this helped!! Have a good day.

7 0
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