Answer:
option B...
they represent different concept...
i hope this will answer your question
Answer:
60 cycles
Explanation:
The first thing we must do to solve the problem is to find how many cycles are presented in 1cm by multiplying the frequency by the base time of the
K=time base=2ms/cm=2x10-3s/cm
f=frecuency=3000s^-1
N=fk
N=(3000)(2x10^-3)=6cycles/cm
Ntot=6x10=60cycles
Answer:
through out the projectile motion the horizontal vilocity remains constant due the absence of the air resistance so the ans is 47.3
Explanation:
A body of mass m has weight
F = GMm/r²
on the surface of the Earth, where G is the universal gravitational constant, M is the mass of the Earth, and r is it's radius.
If the weight is to be halved, then we have
1/2 F = 1/2 GMm/r² = (1/√2)² GMm/r² = GMm/(√2 r²)
so the distance between the body and the planet's center needs to be
√2 × 6.4 × 10⁶ m ≈ 9.1 × 10⁶ m
Answer:
DU = 375 Joules
Explanation:
Given the following data;
Quantity of heat = 500 Joules
Work done = 125 Joules
To find the change in internal energy;
Mathematically, the change in internal energy of a system is given by the formula;
DU = Q - W
Where;
- DU is the change in internal energy.
- Q is the quantity of energy.
- W is the work done.
Substituting into the formula, we have;
DU = 500 - 125
<em>DU = 375 Joules</em>