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3 years ago

When a circuit is arranged in parallel

Physics

1 answer:

attashe74 [19]3 years ago

5 0

Answer:

A. There are multiple paths that electrons can take through the circuit, and it is possible for the electron to pass through one circuit component but not another.

Explanation:

Parallel arrangement of components in an electric circuit puts different parts of the circuit on different branches. In a parallel connection, there are multiple paths for the electrons to take, and it is possible for electrons to pass through on circuit component without going through another. This is the reason why If there is a break in one branch of the circuit, electrons can still flow in other branches, and the same reason why one bulb going off in your home does prevent the other components in your home from coming on (your home is wired in a parallel electric circuit).

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Force F = − + ( 8.00 N i 6.00 N j ) ( ) acts on a particle with position vector r = + (3.00 m i 4.00 m j ) ( ) .

jek_recluse [69]

Explanation:

Given that,

Force, $F=((-8i)+6j)\ N$

Position of the particle, $r=(3i+4j)\ m$

(a) The toque on a particle about the origin is given by :

$\tau=F\times r$

$\tau=((-8i)+6j) \times (3i+4j)$

Taking the cross product of above two vectors, we get the value of torque as :

$\tau=(0+0-50k)\ N-m$

(b) Let $\theta$ is the angle between r and F. The angle between two vectors is given by :

$cos\theta=\dfrac{r.F}{|r|.|F|}$

$cos\theta=\dfrac{(3i+4j).((-8i)+6j)}{(\sqrt{3^2+4^2} ).(\sqrt{8^2+6^2}) }$

$cos\theta=\dfrac{0}{50}$

$\theta=90^{\circ}$

6 0

3 years ago

Two long, parallel wires carry currents of different magnitudes. if the amount of current in each wire is doubled, what happens

Mrac [35]

The force per unit of length between two wires carrying current is
$\frac{F}{L}= \frac{\mu_0 I_1 I_2}{2 \pi r}$
where I1 and I2 are the currents in the two wires, while r is the distance between them.

We can see from the formula that the force is proportional to the product between I1 and I2: $F \sim I_1 I_2$
so, if we double both I1 and I2, we get a factor 4:
$F' \sim (2I_1 )(2I_2)=4 I_1 I_2 =4 F$
so, the force between the wires will be 4 times the original value.

4 0

3 years ago

Potential energy is the energy an object has because of its __________.

jasenka [17]

Answer:

option D

Explanation:

The correct answer is option D

Potential energy of an object is because of its location.

Expression of potential energy

P E = m g H

where H is the height of the object.

g is acceleration due to gravity, 9.8 m/s²

m is the mass of the object.

Potential energy is directly proportional to the location of the object.

If the height of the object is more than the potential energy of the object will also increase.

4 0

3 years ago

I need help with this question, please

Burka [1]

Ok so this is a kinetic and potential energy problem. KE= 1/2*m*v^2 and PE= mgh so we set them equal to each other and get KE=PE so 1/2mv^2=mgh so mass divers out and left with 1/2v^2 =gh so solving for h or height we get
h=(1/2v^2)/g so h= 1/2*(6.5m/s)^2/9.80m/s^2 = 2.16m in height the ball will reach.

Hope this helps! Any questions please just ask!
Please rate to help me out also! Thank you so much!!!

3 0

3 years ago

Read 2 more answers

Find the angle between the vectors. (First find an exact expression and then approximate to the nearest degree.) a = 2i − 5j + k

EastWind [94]

Answer:

Angle=70°

Explanation:

Given data

a=2i-5j+k

b=9i-k

To find

Angle Θ

Solution

As we know from dot product rule that

$a.b=|a||b|cos\alpha \\cos\alpha=\frac{a.b}{|a||b|}\\\alpha=cos^{-1} (\frac{a.b}{|a||b|})$

First we need to find a.b

i.i=j.j=k.k=1

i.j=i.k=j.k=0

$a.b=(18)+(-1)\\a.b=17$

Now for |a| and |b|

$|a|=\sqrt{x^{2} +y^{2}+z^{2} }\\|a|=\sqrt{(2)^{2} +(-5)^{2}+(1)^{2} }\\ |a|=5.477\\And\\|b|=\sqrt{x^{2} +y^{2}+z^{2} }\\|b|=\sqrt{(9)^{2} +(0)^{2}+(-1)^{2} }\\|b|=9.055$

So the angle is given as

$\alpha=cos^{-1} (\frac{a.b}{|a||b|})\\\alpha=cos^{-1} (\frac{17}{(5.477)*(9.055)})\\\alpha =70^{o}$

4 0

3 years ago