Given:
The graph of a function is given.
To find:
The range of the graph.
Solution:
We know that, the domain is the set of input values and range is the set of output values.
In a graph, domain is represented by the x-axis and range is represented by the y-axis.
From the given graph it is clear that there is an open circle at (-8,-8) and a closed circle at (3,4). It means the function is not defined at (-8,-8) but defined for (3,4).
The graph of the function is defined over the interval 
. So, the domain is (-8,3].
The values of the function lie in the interval 
. So, the range is (-8,4].
Therefore, the range of the function are all real values over the interval (-8,4].
Answer:
Well we know that it's a linear because it has a exponent so what we do to answer this question
Step-by-step explanation:
------
- b+ v. b2 -4ac
x= ____________
2a
x2+ 12x +20 =0
a=1
b=12
c=20
_______
X= -12+v 12 2 -4 • 1 • 20
___________________
2•1
Answer:
a = 1, b = 3.
Step-by-step explanation:
a + b = 4
a - b = -2 Adding to eliminate b:
2a = 2
a = 1
So 1 + b = 4
giving b = 3.
Answer:
259.6 ft/sec
Step-by-step explanation:
it is a universal standard that acceleration due to gravity is 32ft/sec^2.
Now it can be verified by equation,
V(f) = V(i)+at (1st equation of motion derived by Newton's three laws of motion)
where,
V(f) is final velocity
V(i) is initial velocity
a is acceleration which is constant and have value 32ft/sec^2
t is time which is given as 7.8 seconds
In the given case, initial velocity that is V(i) will be 0ft/sec. Because, on dropping, object will start to move under the influence of gravity from zero speed.
So,
V(f) = 0 +(32) (7.8)
V(f) = 249.6 ft/sec
Now the condition is given that you have to add a constant 10 to the answer.
so, V(f) = 249.6 + 10
V(f) = 259.6 ft/sec
Answer:
Happy Monday to you too
Step-by-step explanation:
thx for the point
