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loris [4]
3 years ago
15

How is this equation supposed to be solved?

Chemistry
1 answer:
dusya [7]3 years ago
3 0
Multiply straight across! 3*5*2=30, and 4*6*5=120. So, the answer is 30/120, or 1/4.
You might be interested in
He (Helium) is _________ atomic molecule.
babunello [35]

Answer:

Monatomic molecule

Explanation:

Each helium atom has 2 electrons, which is already the maximum no. of electrons that can fit in the first electron shell. When the outermost electron shell is full (2 for the first layer, 8 for others), the atom is stable.

Helium atom itself is already stable, so it doesn't need to combine with another helium atom to form a molecule, hence we call it monatomic.

8 0
3 years ago
Read 2 more answers
Which of the following statements is true?
Lera25 [3.4K]

The  statement  which is true is

metals  lose  electrons  to become cations

<u><em>Explanation</em></u>

  • metals tends  to loss electrons to attain  noble gas  electrons  configuration.
  • When metal loses electrons they form a  positive charged ions.
  • The positively charged ion is known as  cations.
  • for  example  sodium metal (Na)  loses  1 electron to form   a cation with  a charge  of positive 1 ( Na^+)
3 0
3 years ago
Read 2 more answers
The total number of atoms represented by the formula k3fe(cn)6 is:
Brut [27]
<span>K3Fe(CN)6

K - 3 atoms
Fe - 1 atom
C - 6 atoms
N - 6 atoms

Altogether : 3+1+6+6= 16 atoms</span>
4 0
4 years ago
Read 2 more answers
How many grams of K2Cr207 are in 250. mL of 0.500M of K2Cr207:
goldenfox [79]

<u>Analysing the Question:</u>

We are given a 250 mL solution of 0.5M K₂Cr₂O₇

Which means that we have:

0.5 Mole in 1L of the solution

0.125 moles in 250 mL of the solution      <em>[dividing both the numbers by 4]</em>

<em />

<u>Mass of K₂Cr₂O₇ in the given solution:</u>

Molar mass of K₂Cr₂O₇(Potassium Dichromate) = 194 g/mol

<em>we know that we have 0.125 moles in the 250 mL solution provided</em>

Mass = Number of moles * Molar mass

Mass = 0.125 * 194

Mass = 36.75 grams

7 0
3 years ago
Given the standard heats of reaction
ANTONII [103]

Answer:

Explanation:

M(s) → M (g ) + 20.1 kJ --- ( 1 )

X₂ ( g ) → 2X (g ) + 327.3 kJ ---- ( 2 )

M( s) + 2 X₂(g) → M X₄ (g ) - 98.7 kJ ----- ( 3 )

( 3 ) - 2 x ( 2 ) - ( 1 )

M( s) + 2 X₂(g) - 2 X₂ ( g ) - M(s)  → M X₄ (g ) - 98.7 kJ -  2 [ 2X (g ) + 327.3 kJ ] - M (g ) - 20.1 kJ

0 = M X₄ (g ) - 4 X (g ) - M (g ) - 773.4 kJ

4 X (g ) +  M (g ) =  M X₄ (g ) - 773.4kJ

heat of formation of M X₄ (g ) is - 773.4 kJ

Bond energy of one M - X bond =  773.4 / 4 =  193.4 kJ / mole

6 0
3 years ago
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