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postnew [5]
3 years ago
12

Why are there so many different kind of apples

Chemistry
1 answer:
Mars2501 [29]3 years ago
8 0
There are many different types of apples i dont EXACTLY know why but however there are some eople that can only have a certain type of apple
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What is the concentration of a solution in which 10.0 g of AgNO3 is dissolved in 500 mL of solution?
Zigmanuir [339]

molar concentration of AgNO₃ solution = 0.118 mole/L

Explanation:

Because we have the volume of the solution and there is no information about the density of the solution I will asume that you ask for the molar concentration.

number of moles = mass / molecular weight

number of moles of AgNO₃ = 10 / 170 = 0.0588

molar concentration = number of moles / volume (L)

molar concentration of AgNO₃ solution = 0.0588 / 0.5

molar concentration of AgNO₃ solution = 0.118 mole/L

Learn more about:

molar concentration

brainly.com/question/1286583

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3 years ago
How many moles are present in 2.7 liters of Argon gas at STP?
Neko [114]

6.9 cause argon is a proactive system that can be sick

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2 years ago
You will be reading from an essay and a play dealing with the lives of women in the late eighteenth and early
s344n2d4d5 [400]

Answer:

all work

Explanation:

6 0
3 years ago
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at atmoshperic pressure, a balloon contains 2.00L of nitrogen of gas. How would the volume change if the Kelvin temperature were
Nataly [62]

<u>Answer:</u> The percent change in volume will be 25 %

<u>Explanation:</u>

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=2L\\T_1=T_1\\V_2=?\\T_2=75\% \text{ of }T_1=0.75\times T_1

Putting values in above equation, we get:

\frac{2L}{T_1}=\frac{V_2}{0.75\times T_1}\\\\V_2=\frac{2\times 0.75\times T_1}{T_1}=1.5L

Percent change of volume = \frac{\text{Change in volume}}{\text{Initial volume}}\times 100

Percent change of volume = \frac{(2-1.5)}{2}\times 100=25\%

Hence, the percent change in volume will be 25 %

5 0
2 years ago
A machine
rosijanka [135]

i believe the answer is A (((:

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2 years ago
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