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nataly862011 [7]
3 years ago
8

What is the title of the scatter plot?

Mathematics
2 answers:
lbvjy [14]3 years ago
5 0

Answer:

Time and Pages Read

Step-by-step explanation:

Look at the top :)

Ilya [14]3 years ago
3 0
Time and pages read is it
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If necessary, use / for the fraction bar.
LiRa [457]
<h3>Answer:</h3>

2/5

<h3>Step-by-step explanation:</h3>

There are 2 units of green and 5 units of "pink," so the ratio is ...

... green/pink = 2/5

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Cuantos nanómetros soporta el cuerpo
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1 mn diameter self assembled

nature inspired structure

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Jasica Parker would like to have ​$46,000 to buy a new car in 6 years. To accumulate $ 46,000 in 6 ​years, how much should she i
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Answer:  690

Step-by-step explanation:

So, you should do

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3 years ago
What is the unit rate $4.80 for 4 markers?
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3 years ago
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Two professors are applying for grants. Professor Jane has a probability of 0.61 of being funded. Professor Joe has probability
Anna11 [10]

Answer:

  • a. 0.1647;
  • b. 0.7153;
  • c. 0.4453.

Step-by-step explanation:

By definition, if two event A and B are independent, then

P(A\cap B) = P(A) \cdot P(B). (P(A\cap B) is the probability that the outcome of both event A and event B are true.)

<h3>a.</h3>

Since the outcome of these two events are independent,

\begin{aligned}P(\texttt{Jane} \cap \texttt{Joe}) &= P(\texttt{Jane}) \cdot P(\texttt{Joe})\\ &= 0.61 \times 0.27 \\&= 0.1647\end{aligned}.

<h3>b.</h3>

The logic not operator \lnot or the prime superscript ^{\prime} denotes that an event does not happen.  

P(\texttt{Jane}^{\prime}) = 1 - P(\texttt{Jane}) = 1- 0.61 = 0.39.

P(\texttt{Joe}^{\prime}) = 1 - P(\texttt{Joe}) = 1- 0.27 = 0.73.

Since the two events \texttt{Jane} and \texttt{Joe}, \texttt{Jane}^{\prime} and \texttt{Joe}^{\prime} are also independent. Probability that neither professor got funded:

P(\texttt{Jane}^{\prime} \cap \texttt{Joe}^{\prime}) = P(\texttt{Jane}^{\prime}) \cdot P(\texttt{Joe}^{\prime}) = 0.39 \times 0.73 = 0.2847.

Probability that at least one professor got funded- in other words, it is not true that neither professor got funded:

P((\texttt{Jane}^{\prime} \cap \texttt{Joe}^{\prime})^{\prime}) = 1- P(\texttt{Jane}^{\prime} \cap \texttt{Joe}^{\prime}) = 0.7153.

<h3>c.</h3>

Similarly, since the two events \texttt{Jane} and \texttt{Joe}, \texttt{Jane} and \texttt{Joe}^{\prime} are also independent. Probability that Jane but not Joe got funded:

P(\texttt{Jane} \cap (\texttt{Joe}^{\prime})) = P(\texttt{Jane}) \cdot P(\texttt{Joe}^{\prime}) = 0.61 \times 0.73 = 0.4453.

4 0
3 years ago
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