Answer:
C. 32.7%
Explanation:
% composition = ( mass S / mass H2SO4 ) × 100 = 32.08/ 98.10 × 100 = 32.7 % pls mark brainliest
Experiments and investigations must be B. Repeatable.
Answer:
a.3.84m
b.-106.67m/s
c.947.3m/s^2
d.70.17 rad
e.2.5Hz
d.0.4secs
Explanation:
Given x=(7.8)cos[5πrad/s)t+π/3)]
a.Displacement at t=4.4
7.8cos(5π*4.4+π\3)=3.84m
b.velocity
V= dx/dr=-5π(7.8)sin(5πrad/s)t+π\3
at t=4.4
-5π(7.8)sin(5π*4.4+π\3)=-106.67m/s
c.acceleration
a=d^2x/dr^2
-(5π)^2(7.8) cos (5π*t+π\3)
at t=4.4
-(5π)^2(7.8)cos(5π*4.4+π\3)=-947.3m/s^2
d. Phase =(5πrad/s)t+π\3
At t=4.4
5π×4.4+π\3=70.17 rad
e.frequency
Given x= 7.8cos(5πt+π\3
Compare with x=Acos(2πft)
2πft=5πt
F=2.5Hz
f.T=1\f
T=1/2.5=0.4sec
Answer:

Explanation:
= Initial diameter = 4 cm
= Initial velocity = 1 m/s
= Final diameter = 7.8 m
= Final velocity
= Area = 
From the continuity equation we get

The speed of water at the second floor is
.