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musickatia [10]
3 years ago
7

Experiments and investigations must be ____. a. approved b. repeatable c. not reproducible d. accepted

Physics
2 answers:
deff fn [24]3 years ago
7 0
Experiments and investigations must be B. Repeatable.
Dovator [93]3 years ago
5 0
<span>Experiments and investigations must be repeatable. Good experiments allow other fellow researchers to replicate or repeat the studies to examine whether they will create similar results. Such results will further support any theory or hypothesis being questioned. The opposite may also be true, namely the repeating of the experiment may oppose the previous results and put into question the original experiment.</span>
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A theory was not originally a hypothesis. true or false?
Serhud [2]
False.

Theories are hypotheses that have been shown to accurately and predictably explain results obtained through repeated experimentation, to the point where the hypothesis can be assumed to be true. Then, such a hypothesis would be considered a theory.
8 0
4 years ago
If a battery causes a wire to carry a current of 4 Amps how many coulombs of charge flow past any point in the wire in 3 seconds
BabaBlast [244]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

According to above question ~

  • Current (I) = 4 Amperes

  • Time (t) = 3 seconds

  • Charge (q) = ?

Let's find the charge (q) by using formula ~

  • I =  \dfrac{q}{t}

  • 4 =  \dfrac{q}{3}

  • q = 4 \times 3

  • q = 12 \:  \: coulombs

Hence, 12 coulombs of charge flow past any point in the wire in 3 seconds

7 0
3 years ago
If a force of 50 Newton’s was applied to an object with a mass of 500 grams, what will the objects acceleration be?
lapo4ka [179]

Answer:  100 m/s^2

F=ma

Explanation:

50N = 50 kg*m/s^2

500g = 0.5 kg

F=ma

a = F/m

a = (50 kg*m/s^2)/(0.5 kg)

a = 100 m/s^2

5 0
3 years ago
Help with these please someone?
DIA [1.3K]

Answer:

8. 2.75·10^-4 s^-1

9. No, too much of the carbon-14 would have decayed for radiation to be detected.

Explanation:

8. The half-life of 42 minutes is 2520 seconds, so you have ...

1/2 = e^(-λt) = e^(-(2520 s)λ)

ln(1/2) = -(2520 s)λ

-ln(1/2)/(2520 s) = λ ≈ 2.75×10^-4 s^-1

___

9. Reference material on carbon-14 dating suggests the method is not useful for time periods greater than about 50,000 years. The half-life of C-14 is about 5730 years, so at 65 million years, about ...

6.5·10^7/5.73·10^3 ≈ 11344

half-lives will have passed. Whatever carbon 14 may have existed at the time will have decayed completely to nothing after that many half-lives.

7 0
3 years ago
What happens when a light bulb is disconnected in a parralel circuit? ​
VARVARA [1.3K]

Answer:

Hope i could help!

Explanation:

so all but one light could be burned out, and the last one will still function.

5 0
3 years ago
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