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3 years ago

15

You find it hard to ride faster on your bike because a force is pushing back on you. What type of force is slowing you down?

2 answers:

koban [17]3 years ago

8 0

Answer:

as the other person said, it is air resistance

Explanation:

Nataly [62]3 years ago

4 0

Answer by YourHope:

Hi! :)

You find it hard to ride faster on your bike because a force is pushing back on you. What type of force is slowing you down?

C) Air resistance!

Have a BEAUTIFUL day~

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An elevator is moving down with an acceleration of 3.36 m/s2.

sergeinik [125]

Answer : 413.44N

Here it is given that an elevator is moving down with an acceleration of 3.36 m/s² . And we are interested in finding out the apparent weight of a 64.2 kg man . For the diagram refer to the attachment .

From the elevator's frame ( non inertial frame of reference) , we would have to think of a pseudo force.
The direction of this force is opposite to the direction of acceleration the frame and its magnitude is equal to the product of mass of the concerned body with the acceleration of the frame .
When a elevator accelerates down , the weight recorded is less than the actual weight .

From the Free body diagram ,

$\sf\longrightarrow Weight = mg - ma \\$

$\sf\longrightarrow Weight = m ( g - a ) \\$

Mass of the man = 64.2 kg

$\sf\longrightarrow Weight = 64.2( 9.8 - 3.36) N\\$

$\sf\longrightarrow Weight = 64.2 * 6.44 N\\$

$\sf\longrightarrow \underline{\boxed{\bf Weight_{apparent}= 413.44 N }} \\$

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2 years ago

A coil of area 0.320 m2 is rotating at 100 rev/s with the axis of rotation perpendicular to a 0.430 T magnetic field. If the coi

weqwewe [10]

Answer:

The maximum emf generated in the coil is 60527.49 V

Explanation:

Given;

area of coil, A = 0.320 m²

angular frequency, f = 100 rev/s

magnetic field, B = 0.43 T

number of turns, N = 700 turns

The maximum emf generated in the coil is calculated as,

E = NBAω

where;

ω is the angular speed = 2πf

E = NBA(2πf)

Substitute in the given values and solve for E

E = 700 x 0.43 x 0.32 x 2π x 100

E = 60527.49 V

Therefore, the maximum emf generated in the coil is 60527.49 V

8 0

3 years ago

The wave frequency is where 1 hertz equals 1 wave passed a fixed point in 1 second.

ahrayia [7]

   (10 waves) / (5 sec)

   = (10/5) (wave/sec)

   = 2 per sec

   = 2 Hz .

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3 years ago

A machine: A- Makes work easier to do

Vlad1618 [11]

A: makes work easier to do.

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3 years ago

Read 2 more answers

Assume that the force of a bow on an arrow behaves like the spring force. In aiming the arrow, an archer pulls the drawstring ba

Alex

Answer:

v=39.05 m/s

Explanation:

Given that

x= 56 cm

F= 158 N

m= 58 g = 0.058 kg

Lets take spring constant = k

At the initial position,before releasing the arrow

F= k x

By putting the values

F= k x

158= 0.56 k

k=282.14 N/m

Now from energy conservation

Lets take final speed of the arrow after releasing

$\dfrac{1}{2}kx^2=\dfrac{1}{2}mv^2$

k x²=mv²

282.14 x 0.56² = 0.058 v²

v=39.05 m/s

3 0

3 years ago