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2 years ago

15

You find it hard to ride faster on your bike because a force is pushing back on you. What type of force is slowing you down?

2 answers:

koban [17]2 years ago

8 0

Answer:

as the other person said, it is air resistance

Explanation:

Nataly [62]2 years ago

4 0

Answer by YourHope:

Hi! :)

You find it hard to ride faster on your bike because a force is pushing back on you. What type of force is slowing you down?

C) Air resistance!

Have a BEAUTIFUL day~

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You position two plane mirriors at right angles to each other a light ray strikes one mirrior at an angle of 60 to the normal an

Dafna1 [17]

Answer:

30 degrees

Explanation:

Reflects off of mirror 1 at 60 degrees....this makes it incident to second mirror at 30 degrees ....then angle of reflection equals this angle of incidence = 30 degrees

See atached diagram

4 0

2 years ago

A cannon fires a 0.2 kg shell with initial velocity vi = 9.2 m/s in the direction θ = 46 ◦ above the horizontal. The shell’s tra

Sedbober [7]

Answer:

∆h = 0.071 m

Explanation:

I rename angle (θ) = angle(α)

First we are going to write two important equations to solve this problem :

Vy(t) and y(t)

We start by decomposing the speed in the direction ''y''

$sin(\alpha) = \frac{Vyi}{Vi}$

$Vyi = Vi.sin(\alpha ) = 9.2 \frac{m}{s} .sin(46) = 6.62 \frac{m}{s}$

Vy in this problem will follow this equation =

$Vy(t) = Vyi -g.t$

where g is the gravity acceleration

$Vy(t) = Vyi - g.t= 6.62 \frac{m}{s} - (9.8\frac{m}{s^{2} }) .t$

This is equation (1)

For Y(t) :

$Y(t)=Yi+Vyi.t-\frac{g.t^{2} }{2}$

We suppose yi = 0

$Y(t) = Yi +Vyi.t-\frac{g.t^{2} }{2} = 6.62 \frac{m}{s} .t- 4.9\frac{m}{s^{2} } .t^{2}$

This is equation (2)

We need the time in which Vy = 0 m/s so we use (1)

$Vy (t) = 0\\0=6.62 \frac{m}{s} - 9.8 \frac{m}{s^{2} } .t\\t= 0.675 s$

So in t = 0.675 s → Vy = 0. Now we calculate the y in which this happen using (2)

$Y(0.675s) = 6.62\frac{m}{s}.(0.675s)-4.9 \frac{m}{s^{2} } .(0.675s)^{2} \\Y(0.675s) =2.236 m$

2.236 m is the maximum height from the shell (in which Vy=0 m/s)

Let's calculate now the height for t = 0.555 s

$Y(0.555s)= 6.62 \frac{m}{s} .(0.555s)-4.9\frac{m}{s^{2} } .(0.555s)^{2} \\Y(0.555s) = 2.165m$

The height asked is

∆h = 2.236 m - 2.165 m = 0.071 m

6 0

3 years ago

Things that are moving out of phase create an interference pattern<br> TURE or False??

Margarita [4]

Answer:

false

Explanation:

I think I am right with this

8 0

3 years ago

3) All numbers that are divisible by both 3 and 5 are also divisible by 10. Which of the following numbers can be used to show t

zlopas [31]

Answer:

answer E

Explanation:

cuz its 45 is divisible by 3 and 5 but not 10

8 0

2 years ago

a car begins at rest at a stoplight. After the light turns green, the car begins to accelerate 5 m/s squared over the span of 3.

gogolik [260]

Answer: 9m

Explanation:

Our given:

Acceleration- 5m/s^2

Time- 3.6 seconds

Use the equation d = 1/2 • a • t^2

d = 1/2 • 5m/s^2 • 3.6 secs

d = 2.5m/s^2 • 3.6 secs

d = 9m

I hope this is correct

4 0

2 years ago