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3 years ago

What is due to acids formed when atmospheric and volcanic gases mix with water

Physics

1 answer:

Ilya [14]3 years ago

5 0

Answer:

Acid rain results when sulfur dioxide (SO2) and nitrogen oxides (NOX) are emitted into the atmosphere and transported by wind and air currents. The SO2 and NOX react with water, oxygen, and other chemicals to form sulfuric and nitric acids. These then mix with water and other materials before falling to the ground.

Explanation:

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3. A 2kg wooden block whose initial speed is 3 m/s slides on a smooth floor for 2 meters before it comes to a

serious [3.7K]

Answer:

Calculating Coefficient of friction is 0.229.

Force is 4.5 N that keep the block moving at a constant speed.

Explanation:

We know that speed expression is as $\mathrm{V}^{2}=\mathrm{V}_{\mathrm{i}}^{2}+2 . \mathrm{a} . \Delta \mathrm{s}$ .

Where, ${V}_{i}$ is initial speed, V is final speed, ∆s displacement and a acceleration.

Given that,

${V}_{i}$ =3 m/s, V = 0 m/s, and ∆s = 2 m

Substitute the values in the above formula,

$0=3^{2}-2 \times 2 \times a$

0 = 9 - 4a

4a = 9

$a=2.25 \mathrm{m} / \mathrm{s}^{2}$

$a=2.25 \mathrm{m} / \mathrm{s}^{2}$ is the acceleration.

Calculating Coefficient of friction:

$\mathrm{F}=\mathrm{m} \times \mathrm{a}$

$\mathrm{F}=\mu \times \mathrm{m} \times \mathrm{g}$

Compare the above equation

$\mu \times m \times g=m \times a$

Cancel "m" common term in both L.H.S and R.H.S

$\text { Equation becomes, } \mu \times g=a$

$\text { Coefficient of friction } \mu=\frac{a}{g}$

$\mathrm{g} \text { on earth surface }=9.8 \mathrm{m} / \mathrm{s}^{2}$

$\mu=\frac{2.25}{9.8}$

$\mu=0.229$

Hence coefficient of friction is 0.229.

calculating force:

$\text { We know that } \mathrm{F}=\mathrm{m} \times \mathrm{a}$

$\mathrm{F}=2 \times 2.25 \quad(\mathrm{m}=2 \mathrm{kg} \text { given })$

F = 4.5 N

Therefore, the force would be 4.5 N to keep the block moving at a constant speed across the floor.

7 0

3 years ago

A mass weighing pounds is attached to a spring whose constant is lb/ft. The medium offers a damping force that is numerically eq

andreyandreev [35.5K]

Answer:

hello your question has some missing values attached below is the complete question with the missing values

answer :

a) 0.083 secs

b) 0.33 secs

c) 3e^-4/3

Explanation:

Given that

g = 32 ft/s^2 , spring constant ( k ) = 2 Ib/ft

initial displacement = 1 ft above equilibrium

mass = weight / g = 4/32 = 1/8

damping force = instanteous velocity hence β = 1

a)Calculate the time at which the mass passes through the equilibrium position.

time mass passes through equilibrium = 1/12 seconds = 0.083

b) Calculate the time at which the mass attains its extreme displacement

time when mass attains extreme displacement = 1/3 seconds = 0.33 secs

c) What is the position of the mass at this instant

position = 3e^-4/3

attached below is the detailed solution to the given problem

6 0

3 years ago

How does what happens to the particles in a substance during melting differ from what happens during freezing?

sasho [114]

When in the melting process particles start to move more freely when in the freezing process particles tend to slow and vibrate in place

8 0

3 years ago

You need to pull up the cart up this ramp. How would you change this ramp so it is easier to pull the cart up?

natali 33 [55]

I would make the ramp flatter. In doing so the ramp would have to be longer.

6 0

4 years ago

Add a picture of leaves.

iren2701 [21]

Answer:

There you go

Explanation:

6 0

4 years ago