We know that every object exerts an attraction on every other object and the heavier the object ___ the attraction.
1 answer:
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Answer:
k = 49 N/m
Explanation:
Given that,
Mass, m = 250 g = 0.25 kg
When the mass is attached to the end of the spring, it elongates 5 cm or 0.05 m. We need to find the spring constant. Let it is k.
The force due to mass is balanced by its weight as follows :
mg=kx
So, the spring constant of the spring is 49 N/m.
The astronaut final velocity is 0.06 m/s to the right
Explanation:
In absence of external forces, the total momentum of the box-astronaut system is conserved.
At the beginnig, the total momentum of the two is zero, since they are at rest:
While the final momentum, after the astronaut throws the box, is:
where
m = 11 kg is the mass of the box
M = 79 kg is the mass of the astronaut
v = -0.45 m/s (to the left) is the velocity of the box (we take left as negative direction)
V is the final velocity of the astronaut
The total momentum is conserved, so
And solving , we find V:
And the positive sign indicates that the direction is to the right.
Learn more about momentum:
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