D. 0.0001.......first the zero before the decimal point is devided by 2....so it gives out 0 as a reminder so u right 0. at first then to do the part after decimal...first multiply 0.625 by 2 which gives out 0.125 as a fractional number so 0 would be the number after "0." ...and again the answer 0.125 is multiplied by 2 which gives out 0.25....so again we get a zero as an integer so now it would be "0.00..." ....again multiply 0.25 by 2 which gives out 0.5....again the integer is 0....so we add another 0 after 0.00....which would then become 0.000.....after that again multiply 0.5 by 2 which would give 1 as a result....as the fractional part is over, u need to stop here....so add that 1 after the 0.000 which gives 0.0001 as a final result.
Answer:
The correct answer to this question is given below in the explanation section.
Explanation:
This question is about integrated development environments (IDEs) that support multiple high-level programming languages.
All mentioned IDEs such as Eclipse, Visual Studio, and Xcode support multiple high-level programming languages except Linux.
Using Eclipse, you can do Java programming easily and can build Java-based programs, and also you can do android programming in Eclipse while importing required android settings and libraries. Visual Studio is a Microsoft IDE, in which you can build desktop, web, and mobile, and windows phone app easily using high-level programming. Xcode is an integrated development environment for macOS containing a suite of software development tools developed by Apple for developing software for macOS, iPadOS, iOS, watchOS, and tvOS.
While Linux is not an IDEs, it is an open-source operating system based on Linux kernel.
Answer:
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The recursive function divBy3And5 is defined in Python and is found in the attached image.
In the base case, the function divBy3And5 tests if the input list is empty. If so, the tuple returned is
. This means no numbers are divisible by three and no numbers are divisible by five.
The recursive step gets the first element of the list and
- If divisible by 3, it sets <em>count_of_3</em> to 1, else it leaves it as 0
- If divisible by 5, it sets <em>count_of_5</em> to 1, else it leaves it as 0
It then makes a recursive call on the remaining elements, and stores it in a variable as follows
<em>divBy3And5_for_remaining_elem</em> = divBy3And5(remaining_elements)
Then, it returns the tuple
(<em>divBy3And5_for_remaining_elem</em>[0] + <em>count_of_3</em>,
<em>divBy3And5_for_remaining_elem</em>[1] + <em>count_of_5)</em>
Learn more about recursion in Python: brainly.com/question/19295093