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Gre4nikov [31]
3 years ago
6

HALP! HALP MEHHHH! What is the mean of the values in the stem-and-leaf plot?

Mathematics
1 answer:
lawyer [7]3 years ago
4 0
Just organized them. Order:
15, 18, 46, 50, 50 ,50, 50, 57
 
Add them up, which is 336. Divide that by 2, and the mean is 168
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31-18÷6 how would you solve this using PEMDAS?
sergeinik [125]
P: Parenthesis
E: Equation 
M:Multiplication 
D: Division 
A : addition 
S: Subtraction

So first you need to divide because it is before so you divide 18 by 6 which is 3 then you subtract (31 - 3) which gives you 28
answer : 28

7 0
3 years ago
Read 2 more answers
What is the value of the expression below?<br> 32^3/5<br> O A. 6/5<br> B. 6<br> O c. 96/5<br> O D. 8
Hoochie [10]

Answer:

D. 8

Step-by-step explanation:

32^(3/5) is the same as \sqrt[5]{32}^3.

 \sqrt[5]{32} = 2 because 2^5=32

2^3 = 8

6 0
2 years ago
Read 2 more answers
Solve - pv + 40 &lt; 65 for v<br> solve 7w - 3r = 15 for r
Katarina [22]

Answer:

v > -25/p

r = -5 +7/3 w

Step-by-step explanation:

- pv + 40 < 65

Subtract 40 from each side

- pv + 40-40 < 65-40

-pv < 25

Divide each side by -p  (remember to flip the inequality since we are dividing by a negative)

-pv/-p > 25/-p

v > -25/p


7w - 3r = 15

Subtract 7w from each side

7w-7w - 3r = 15-7w

-3r = 15-7w

Divide by -3

-3r/-3 = (15-7w)/-3

r = -5 +7/3 w

8 0
3 years ago
How do I do this equation? Need help please <br> Will mark brainliest
jenyasd209 [6]
The x (the second one) has a one in front of it so 5x *1x=5x so 5x-4 is the answer
4 0
3 years ago
Read 2 more answers
Suppose a simple random sample of size nequals45 is obtained from a population with muequals64 and sigmaequals14. ​(a) What must
jeka94

Answer:

Step-by-step explanation:

Given that sample size = n=45

mu = 64 and sigma =14

a) Sample mean will follow a normal distribution irrespective of the original distributions provided

i) samples are randomly drawn

ii) samples represent the population

iii) Sample size is sufficiently large

b) Here we have sample std dev= \frac{\sigma}{\sqrt{n} } \\=\frac{14}{\sqrt{45} } \\=2.09

P(X bar>68.1) = P(Z>\frac{68.1-64}{2.09} \\=P(Z>1.96)\\=0.25

c) P(X bar>66.3) = P(Z>\frac{66.3-64}{2.09} \\=P(Z>1.10)\\=0.136

7 0
3 years ago
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