What are the x intercepts of the quadratic? (0,0) (0,-1) (-1,0) There are none.

Karen went to the farmers market

Zinaida [17]

Answer:

6 papayas and 11 pineapples

Step-by-step explanation:

So, we need to find an answer of how many papayas and pineapples she bought, and we only spent $48.

So, papayas are $2.50 each, and Pineapples are $3.00 each and we only bought 17 fruits total.

lets try 8 papayas, and 9 Pineapples.

$2.50 x 8 = $20.00 total on Papayas

$3.00 x 9 = $27.00 total on Pineapples.

That would only be $47 spent total.

Lets try 10 papayas and 7 pineapples.

$2.50 x 10 = $25.00

$3.00 x 7 = $21.00

That would only be a total of $26 spent.

Lets try 6 papayas and 11 pineapples.

$2.50 x 6 = $15.00

$3.00 x 11 = $33.00

This would be a total of $48 spent.

8 0

3 years ago

I don't understand how to solve this. Can someone help me?

Marat540 [252]

Answer: 62-48=14

Step-by-step explanation: therefor the bottom right hand corner is 14.

hope this is right ;)

7 0

3 years ago

Read 2 more answers

Benjamin writes an expression for the sum of 1 cubed, 2 cubed, and 3 cubed -- What is the value of the expression? options---

saw5 [17]

Answer:

36

Step-by-step explanation:

1^3 + 2^3 + 3^3= 1+8+27

9+27= 36

7 0

3 years ago

please help me, Prove a quadrilateral with vertices G(1,-1), H(5,1), I(4,3) and J(0,1) is a rectangle using the parallelogram me

mestny [16]

Answer:

Step-by-step explanation:

We are given the coordinates of a quadrilateral that is G(1,-1), H(5,1), I(4,3) and J(0,1).

Now, before proving that this quadrilateral is a rectangle, we will prove that it is a parallelogram. For this, we will prove that the mid points of the diagonals of the quadrilateral are equal, thus

Join JH and GI such that they form the diagonals of the quadrilateral.Now,

JH= $\sqrt{(5-0)^{2}+(1-1)^{2}}=5$ and

GI= $\sqrt{(4-1)^{2}+(3+1)^{2}}=5$

Now, mid point of JH= $(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

= $(\frac{5+0}{2},\frac{1+1}{2})=(\frac{5}{2},1)$

Mid point of GI= $(\frac{5}{2},1)$

Since, mid point point of JH and GI are equal, thus GHIJ is a parallelogram.

Now, to prove that it is a rectangle, it is sufficient to prove that it has a right angle by using the Pythagoras theorem.

Thus, From ΔGIJ, we have

$(GI)^{2}=(IJ)^{2}+(JG)^{2}$ (1)

Now, JI= $\sqrt{(4-0)^{2}+(3-1)^{2}}=\sqrt{20}$ and GJ= $\sqrt{(0-1)^{2}+(1+1)^{2}}=\sqrt{5}$

Substituting these values in (1), we get

$5^{2}=(\sqrt{20})^{2}+(\sqrt{5})^{2} }$

$25=20+5$

$25=25$

Thus, GIJ is a right angles triangle.

Hence, GHIJ is a rectangle.

Also, The diagonals GI= $\sqrt{(4-1)^{2}+(3+1)^{2}}=5$ and HJ= $\sqrt{(0-5)^2+(1-1)^2}=5$ are equal, thus, GHIJ is a rectangle.

6 0

3 years ago

Find the slope of the line passing through (-8,6) and (6,6)

frosja888 [35]

Answer:

0

Step-by-step explanation:

6-6 equals 0 and -8 minus 6 equals -14 and 0 divided by equals 0

8 0

4 years ago