Answer:
If an equation has no solution, then the solution set is the _<u>empty set</u>_ and
is denoted by _<u>{ } </u><u>or </u><u>∅</u>__.
A)Plugging in our initial statement values of y = 16 when x = 10, we get:
16 = 10k
Divide each side by 10 to solve for k:
16/10=
k = 1.6
Solve the second part of the variation equation:
Because we have found our relationship constant k = 1.6, we form our new variation equation:
y = 1.6x
Since we were given that x, we have
y = 1.6()
y = 0
B)Plugging in our initial statement values of y = 1 when x = 15, we get:
1 = 15k
Divide each side by 15 to solve for k:
1/15
=15k
k = 0.066666666666667
Answer:
2 additional premium channels
Step-by-step explanation:
Using the given function, we substitute c(x) = 114 and solve for x:
114 =90 + 12x
Subtract 90 from both sides:
24=12x
Divide both sides by 12:
2=x
So you have ordered 2 additional premium channels.
Do you have a graphing calculator? if yes than all you have to do is hit the y= button in the top left corner and type 1/4x-4 for y1. then you need to hit graph in the top right corner. repeat this process substituting 1/4x-4 and -x+1
Answer:
I would multiply the first equation by −4 and the second by 3 and add together the two equatins (in columns): ... Step 2. Prepare the equations. Multiply every term in each equation by a ... Subtract Equation (4) from Equation (3). ... How do you solve the system 5x−10y=15 and 3x−2y=3 by multiplication?
