So we cant do anything until the 'y' in the 2nd problem is by the 2x. So after we move the 2x over the equation will look like this, "-2x+y=-6."
Now that that is set up we can make our equation.
(12x+5y=30) - (-2x+y=-6)
We have to multiply the second equation by -6 in order to cancle out the X's. That comes out to (12x-6y=36)
Now the equation looks like (12x+5y=30) - (12x+6y=36)
After you subtract you have (-y=-6)
divide by (-1) and you're left with y=6
Answer:
10 games
Step-by-step explanation:
Let C be cost and x be number of games
Arcade A: C = 5 + 0.6x
Arcade B: C = 7 + 0.4x
for both arcades to be the same price, Both C's must be equal, hence we equate the right side of both equations:
5 + 0.6x = 7 + 0.4x (subtract 5 fromboth sides)
0.6x = 7 + 0.4x - 5
0.6x = 2 + 0.4x (subtract 0.4x from both sides)
0.6x - 0.4x = 2
0.2x = 2 (divide both sides by 0.2)
x = 2 / (0.2)
x = 10
Answer: 0
Step-by-step explanation:
The disciminant \Delta tells you how many real solutions a quadratic equation has, depending on its sign:
\Delta>0\implies\text{2 solutions}\\\Delta=0\implies\text{1 solution}\\\Delta<0\implies\text{no solutions}
Answer:
(7,0)
Step-by-step explanation:
