Answer:
E=1100V/m
Explanation:
Given required <u>solution</u>
V=6.6v E=? V=Ed ; V is the potential difference between
d=D/2=1.2cm/2=0.6cm=0.006m the halfway
E is the electric field between the two
plates.
d is the distance between the halfway.
So we can use the above formula to calculate the electric field.
V=Ed from this E=V/d substitute the values from the given equation.
E=6.6v/0.006m
E= 1100 v/m
Answer:
a) r eq = -a/(2b)
b) k = a/r eq = -2b
Explanation:
since
U(r) = ar + br²
a) the equilibrium position dU/dr = 0
U(r) = a + 2br = 0 → r eq= -a/2b
b) the Taylor expansion around the equilibrium position is
U(r) = U(r eq) + ∑ Un(r eq) (r- r eq)^n / n!
,where Un(a) is the nth derivative of U respect with r , evaluated in a
Since the 3rd and higher order derivatives are =0 , we can expand until the second derivative
U(r) = U(r eq) + dU/dr(r eq) (r- r eq) + d²U/dr²(r eq) (r- r eq)² /2
since dU/dr(r eq)=0
U(r) = U(r eq) + d²U/dr²(r eq) (r- r eq)² /2
comparing with an energy balance of a spring around its equilibrium position
U(r) - U(r eq) = 1/2 k (r-r eq)² → U(r) = U(r eq) + 1/2 k (r-r eq)²
therefore we can conclude
k = d²U/dr²(r eq) = -2b , and since r eq = -a/2b → -2b=a/r eq
thus
k= a/r eq
The electric force between two charge objects is calculated through the Coulomb's law.
F = kq₁q₂/d²
The value of k is 9.0 x 10^9 Nm²/C² and the charge of proton is 1.602 x10^-19 C. Substituting the known values from the given,
2.30x10^-26 = (9.0 x 10^9 Nm²/C²)(1.602 x10^-19C)²/d²
The value of d is equal to 0.10 m.
Answer:
option b ) is correct
Explanation:
Let d be the distance in km from the place of lightning . velocity of sound is 340 m /s approx
in km/ s it is 0.34 km/s
time in sec taken by sound to cover a distance of d km
d / .34 = t
d = .34 t
d =
d = t / 3
so option b ) is correct . ,