How does the moons diameter compare with the distance between the earth and the moon?

A 500-W heating coil designed to operate from 110V is made of Nichrome wire 0.500 mm in diameter. (b) What If? Now consider the

melamori03 [73]

The power delivered to the coil is 721.31 Watts

<h3>How to determine the power</h3>

Given that;

Power of the heating coil = 500W
Voltage = 110V
Diameter of the Nichrome wire = 0. 500mm, radius = 0. 500/2 = 0. 00025m

But the formula for power is given a;

Power, P = V²/R

Then , R = V²/P

R = (110)²/ 500 = 24. 2Ω

To determine the length,

Length, L = RA/ ρ

L = 24. 2 × ( 0. 0025)² × 3. 142/ 10^-6

L = 4. 32m

We also have that;

Resistance, R = Ro( 1 + α ΔT)

R = 24. 2 ( 1 + 0. 0004 × 1180)

R = 35. 62Ω

Current, I = V R

Current, I = 110/24.2 = 4. 5 A

Power delivered = I²R = (4.5)² × 35. 62 = 721.31 Watts

Thus, the power delivered to the coil is 721.31 Watts

Learn more about power here:

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6 0

1 year ago

The Sun appears to move across the sky during the day. The best explanation for this apparent motion is that Earth is

Harrizon [31]

Answer:

C

Explanation:

5 0

2 years ago

Read 2 more answers

A 1,103 kg car traveling at 18 m/s to the south collides with a 4,919 kg truck that is initially at rest at a stoplight. The car

Zigmanuir [339]

ANSWER

$3.30\text{ m/s}$

EXPLANATION

Parameters given:

Mass of car, mc = 1103 kg

Mass of truck, mt = 4919 kg

Initial velocity of car, uc = 18 m/s

Inital velocity of truck = 0 m/s

To solve this problem, we have to apply the law of conservation of momentum, which states that the total momentum of a system is constant.

This implies that:

$m_cu_c+m_tu_t=m_cv_c+m_tv_t$

Since the car and the truck stick together after the collision, they will have the same final velocity.

Hence:

$m_cu_c+m_tu_t=(m_c+m_t)v_{}_{}$

Substitute the given values and solve for v (final velocity):

$\begin{gathered} (1103\cdot18)+(4919\cdot0)=(1103+4919)v \\ \Rightarrow19854=6022v \\ \Rightarrow v=\frac{19854}{6022} \\ v=3.30\text{ m/s} \end{gathered}$

That is the final velocity of the two-vehicle mass.

8 0

7 months ago

A 190 g rock at 20°C is completely immersed in 600 g of water at 80°C. Which one of the following statements is true right after

Umnica [9.8K]

Rock is completely immersed in hot water. By the second law of thermodynamics, thermal energy or heat is transferred from substance with higher temperature to substance with lower temperature until they come to thermal equilibrium i.e. both at same temperature.

It is given here that rock is at 20°C which is at lower temperature than water at 80°C. ∴Heat or thermal energy flows from water to rock. So, right choice is-

A. The water gives the rock thermal energy and gets no thermal energy in return.

8 0

2 years ago

A railroad car moving at a speed of 3.46 m/s overtakes, collides and couples with two coupled railroad cars moving in the same d

I am Lyosha [343]

Answer:

$2.09\ \text{m/s}$

$22298.4\ \text{J}$

Explanation:

m = Mass of each the cars = $1.6\times 10^4\ \text{kg}$

$u_1$ = Initial velocity of first car = 3.46 m/s

$u_2$ = Initial velocity of the other two cars = 1.4 m/s

v = Velocity of combined mass

As the momentum is conserved in the system we have

$mu_1+2mu_2=3mv\\\Rightarrow v=\dfrac{u_1+2u_2}{3}\\\Rightarrow v=\dfrac{3.46+2\times 1.4}{3}\\\Rightarrow v=2.09\ \text{m/s}$

Speed of the three coupled cars after the collision is $2.09\ \text{m/s}$ .

As energy in the system is conserved we have

$K=\dfrac{1}{2}mu_1^2+\dfrac{1}{2}2mu_2^2-\dfrac{1}{2}3mv^2\\\Rightarrow K=\dfrac{1}{2}\times 1.6\times 10^4\times 3.46^2+\dfrac{1}{2}\times 2\times 1.6\times 10^4\times 1.4^2-\dfrac{1}{2}\times 3\times 1.6\times 10^4\times 2.09^2\\\Rightarrow K=22298.4\ \text{J}$

The kinetic energy lost during the collision is $22298.4\ \text{J}$ .

6 0

2 years ago