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mr_godi [17]
3 years ago
9

A ray of white light moves through the air and strikes the surface of water in a beaker. The index of refraction of the water is

1.33 and the angle of incidence is 30 degrees. All of the following are true EXCEPT:_________
I. the angle of reflection is 30 degrees
II. the angle of refraction is 30 degrees
III. total internal reflection will result, depending on the critical angle
Physics
1 answer:
ziro4ka [17]3 years ago
8 0

Answer:

All of the following are true EXCEPT, the angle of refraction is 30 degrees

Explanation:

It is given that,        

The index of refraction of the water is 1.33 and the angle of incidence is 30 degrees. We know that when a ray of white light moves through the air and strikes the surface of water in a beaker, refraction occurs. Let r is the angle of refraction. It can be calculated using Snell's law as :

n=\dfrac{sin\ i}{sin\ r}

sin\ r=\dfrac{sin\ i}{n}

sin\ r=\dfrac{sin(30)}{1.33}

r=22.08^{\circ}

So, the angle of refraction is 22.08 degrees.

According to the law of reflection, the angle of incidence is equal to the angle of reflection. Since, it is incident at an angle of 30 degrees, so the angle of reflection will be 30 degrees. Also, total internal reflection will result, depending on the critical angle.

So, the wrong statement is the angle of refraction is 30 degrees. It is equal to 22.08 degrees.

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The total energy of a block—spring system is 0.18 J. The amplitude is 14.0 cm and the maximum speed is 1.25 m/s. Find: (a) the m
algol13

a) The mass is 0.23 kg

b) The spring constant is 1.25 N/m

c) The frequency is 1.42 Hz

d) The speed of the block is 1.08 m/s

Explanation:

a)

We can find the mass of the block by applying the law of conservation of energy: in fact, the total mechanical energy of the system (which is sum of elastic potential energy, PE, and kinetic energy, KE) is constant:

E=PE+KE=const.

The potential energy is given by

PE=\frac{1}{2}kx^2

where k is the spring constant and x is the displacement. When the block is crossing the position of equilibrium, x = 0, so all the energy is kinetic energy:

E=KE_{max}=\frac{1}{2}mv_{max}^2 (1)

where

m is the mass of the block

v_{max}=1.25 m/s is the maximum speed

We also know that the total energy is

E=0.18 J

Re-arranging eq.(1), we can find the mass:

m=\frac{2E}{v_{max}^2}=\frac{2(0.18)}{(1.25)^2}=0.23 kg

b)

The maximum speed in a spring-mass system is also given by

v_{max} =\sqrt{\frac{k}{m}} A

where

k is the spring constant

m is the mass

A is the amplitude

Here we have:

v_{max}=1.25 m/s is the maximum speed

m = 0.23 kg is the mass

A = 14.0 cm = 0.14 m is the amplitude

Solving for k, we find the spring constant

k=\frac{v_{max}^2}{A^2}m=\frac{1.25^2}{0.14^2}(0.23)=18.3 N/m

c)

The frequency in a spring-mass system is given by

f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}

where

k is the spring constant

m is the mass

In this problem, we have:

k = 18.3 N/m is the spring constant (found in part b)

m = 0.23 kg is the mass (found in part a)

Substituting and solving for f, we find the frequency of the system:

f=\frac{1}{2\pi}\sqrt{\frac{18.3}{0.23}}=1.42 Hz

d)

We can solve this part by using the law of conservation of energy; in fact, we have

E=PE+KE=\frac{1}{2}kx^2 + \frac{1}{2}mv^2

Where v is the speed of the system when the displacement is equal to x.

We know that the total energy of the system is

E = 0.18 J

Also we know that

k = 18.3 N/m is the spring constant

m = 0.23 kg is the mass

Substituting

x = 7.00 cm = 0.07 m

We can solve the equation to find the corresponding speed v:

v=\sqrt{\frac{2E-kx^2}{m}}=\sqrt{\frac{2(0.18)-(18.3)(0.07)^2}{0.23}}=1.08 m/s

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3 0
3 years ago
How did you know if an electric current is<br> flowing in a lightbulb?
sweet [91]

Answer:

if it lights up

Explanation:

electricity

7 0
3 years ago
A truck is traveling 70.0 kph away from you. The driver is blowing the horn, which has a frequency of 400 Hz. The air temperatur
Helga [31]
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4 0
3 years ago
Describe the motion of an automobile on an east-west
Tanya [424]

Answer:

1. The automobile is traveling due east and is speeding up.

2. The car is traveling due east and is is slowing down.

3. The automobile is traveling due east at a constant speed.

4. The car is traveling due west and is slowing down.

5. The automobile is traveling due west and is speeding up.

6. The automobile is traveling due west at a constant speed.

7. The automobile is accelerating due east from rest.

8. The automobile is accelerating due west from rest.

Explanation:

The key to understanding this is:

When the acceleration and initial velocity of the automobile have the same sign (positive or negative) then the automobile is speeding up. Explained further, if acceleration and the initial velocity are both positive or they are both negative the automobile is speeding up but whenever they have opposite signs (that is acceleration is positive and initial velocity is negative or vice versa) the automobile is slowing down. When the acceleration is zero the automobile is maintaining a unform motion at a constant speed (the speed is not changing with time). The + or - sign indicates the direction of travel. In this case east is + and west is -. It is my pleasure answering this question. I hope you find it helpful. Thank you.

4 0
3 years ago
If the index of refraction for a certain glass is 1.5, and the angle of refraction is 15 degrees for a ray of light
LiRa [457]

Answer:

\theta_i = 23^o

Explanation:

The refractive index of a medium is given by the following formula:

\eta = \frac{Sin\theta_i}{Sin\theta_r}

where,

η = refractive index = 1.5

\theta_i = angle of incidence = ?

\theta_r = angle of refraction = 15°

Therefore,

1.5 = \frac{Sin\theta_i}{Sin15^o}\\\\Sin\theta_i=(1.5)Sin15^o\\\\\theta_i = Sin^{-1}(0.388)\\\\

\theta_i = 23^o

4 0
3 years ago
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