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Anvisha [2.4K]
3 years ago
13

The magnitude of the electric force between two protons is 2.30 10-26 n. how far apart are they?

Physics
2 answers:
SCORPION-xisa [38]3 years ago
7 0
The electric force between two charge objects is calculated through the Coulomb's law.
                               F = kq₁q₂/d²
The value of k is 9.0 x 10^9 Nm²/C² and the charge of proton is 1.602 x10^-19 C. Substituting the known values from the given,
                           2.30x10^-26 = (9.0 x 10^9 Nm²/C²)(1.602 x10^-19C)²/d²
The value of d is equal to 0.10 m. 
Feliz [49]3 years ago
7 0

Answer:

0.079m

Explanation:

According to coulombs law, the force of attraction between two charges is directly proportional to the product of the charges and inversely proportional to the square of their distance between them.

Mathematically, F = kq1q2/d² where

k is the coulombs constant

F is the force between the charges

q1 and q2 are the charges

d is the distance between the charges

Given F = 2.30×10^-26

d = ?

q1 = q2 = 1.602 x10^-19 C.

k = 9×10^9N/C²m²

Note that charge of proton is 1.602 x10^-19 C.

Substituting the values in the formula to get 'd' we have;

2.3×10^-26 = 9×10^9×(1.602×10^-19)²/d²

2.3×10^-26d² = 9×10^9×(1.602×10^-19)²

2.3×10^-26d² = 9×10^9×1.602×10^-38

2.3×10^-26d² = 1.442×10^-28

d² = 1.442×10^-28/2.3×10^-26

d² = 0.627×10^-2

d² = 0.00627

d = √0.00627

d = 0.079m

It means they are 0.079m apart

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Explanation:

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2 years ago
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Two loudspeakers (A and B) are 3.20m apart and emitting a sound with a frequency of 400Hz. An observer is 2.10m directly in fron
TiliK225 [7]

Answer:

The observer hears a loud sound

Explanation:

In order to know if the observer hears a loud or a quiet sound, you need to know if there is a constructive or destructive interference between the sound waves of the loudspeakers.

You first calculate the distance between the observer and the loudspeakers.

The distances are given by:

d1: distance to loudspeaker A = 2.10m

d2: distance to loudspeaker B

d_2=\sqrt{(3.20m)^2+(2.10m)^2}=3.827m

Next, you calculate the wavelength of the sound waves by using the following formula:

\lambda=\frac{v_s}{f}

vs: speed of sound =  343 m/s

f: frequency of the waves = 400Hz

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\lambda=\frac{343m/s}{400Hz}=0.8575m

Next, you calculate the path difference between the distance from the observer to the loudspeakers:

\Delta d=3.827m-2.10m=1.727m

You obtain a constructive interference (loud sound) if the quotient between the wavelength of the sound and the difference path is an integer:

\frac{\Delta d}{\lambda}=\frac{1.727m}{0.857}\approx2

Then, there will be a constructive interference, and the sound who the observer hears is loud.

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What is the basic equation that defines velocity?
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