Answer:
828 kg/m³ or 0.828 g/cm³
Explanation:
Applying,
D = m/V............. Equation 1
Where D = density of the liquid, m = mass of the liquid, V = volume of the liquid.
From the question,
Given: m = 77 g , V = 93 cm³
Substitute these values into equation 1
D = 77/93
D = 0.828 g/cm³
Converting to kg/m³
D = 828 kg/m³
Force = Work/distance
Force = 150/10
= 15 Newtons
Force = 15 Newtons
Therefore, 15 newtons of force is applied to the body when 150 joules of work
is done in displacing the body through a distance of 10m in the direction of the force.
Explanation:
Terminal velocity is given by:
Here, m is the mass of the falling object, g is the gravitational acceleration, 
is the drag coefficient, 
is the fluid density through which the object is falling, and A is the projected area of the object. in this case the projected area is given by:
Recall that drag coefficient for a horizontal skydiver is equal to 1 and air density is 
.
Without drag contribution the motion of the person is an uniformly accelerated motion, thus:
Answer:
<h3>The answer is 5.4 kg</h3>
Explanation:
The mass of the object can be found by using the formula
f is the force
a is the acceleration
From the question we have
We have the final answer as
<h3>5.4 kg</h3>
Hope this helps you
