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2 years ago

A 25 N force acts on a box moving along a plane at a distance of 20 meters. What is the work it does with this force?

Physics

1 answer:

SpyIntel [72]2 years ago

5 0

Answer:

500 J.

Explanation:

Work done = force * distance

= 25 * 20

= 500 Joules.

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A catapult launches a test rocket vertically upward from a well, giving the rocket an initial speed of 80.6 m/s at ground level.

galina1969 [7]

Answer:

44.64 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.8 m/s²

$v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 4.2\times 1180+80.6^2}\\\Rightarrow v=128.01\ m/s$

$v=u+at\\\Rightarrow 128.01=80.6+4.2t\\\Rightarrow t=\frac{128.01-80.6}{4.2}=11.29\ s$

Time taken to reach 1180 m is 11.29 seconds

$v=u+at\\\Rightarrow 0=128.01-9.8t\\\Rightarrow t=\frac{128.01}{9.8}=13.06\ s$

Time the rocket will keep going up after the engines shut off is 13.06 seconds.

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-128.01^2}{2\times -9.8}\\\Rightarrow s=836.05\ m$

The distance the rocket will keep going up after the engines shut off is 836.05 m

Total distance traveled by the rocket in the upward direction is 1180+836.05 = 2016.05 m

The rocket will fall from this height

$s=ut+\frac{1}{2}at^2\\\Rightarrow 2016.05=0t+\frac{1}{2}\times 9.8\times t^2\\\Rightarrow t=\sqrt{\frac{2016.05\times 2}{9.8}}\\\Rightarrow t=20.29\ s$

Time taken by the rocket to fall from maximum height is 20.29 seconds

Time the rocket will stay in the air is 11.29+13.06+20.29 = 44.64 seconds

5 0

3 years ago

A 1250 kg car starts from rest and speeds up to 14.0 m/s in 7.25s. How much force acted on the car ?

densk [106]

M = 1250 kg
V = 14.0 m/s
t = 7.25 s
F = ?

Impulse equation
F . t = m . V

:. F = mv/t

F = (1250 kg x 14.0 m/s) / 7.25s

F = 2414 N

4 0

4 years ago

How many miles is in 7 blocks?

borishaifa [10]

Answer:

Different street blocks are different lengths, so it won't be possible to answer this.

8 0

3 years ago

How much heat is required to increase the temperature of 100.0 grams of iron from 15.0oC to 40.2oC? (The specific heat of iron i

Lesechka [4]

The heat required to increase temp is 1150 j

7 0

3 years ago

Read 2 more answers

You raise a bucket of water from the bottom of a deep well. if your power output is 138 w , and the mass of the bucket and the w

inn [45]

Maybe 34.5

I'm not quite sure

8 0

4 years ago