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3 years ago

S= 2Lw+2wh+5hL solve for h

1 answer:

8 0

$S=2Lw+2wh+5hL\ \ \ \ \ |subtract\ 2Lw\ and\ 2wh\ from\ both\ sides\\\\5hL=S-2Lw-2wh\ \ \ \ \ |divide\ both\ sides\ by\ 5L\\\\\boxed{h=\dfrac{S-2Lw-2wh}{5h}}$

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Using the identity sin? O + cos? O = 1, find the value of tan O, to the nearest

Novosadov [1.4K]

Answer:

3.7

Step-by-step explanation:

Given

sin²θ + cos²θ = 1
sinθ = 0.27

Solving for cosθ

cos²θ = 1 - sin²θ
cos²θ = 1 - (0.27)²
cos²θ = 0.0729

Finding tanθ

tanθ = sinθ / cosθ
tanθ = 0.27 / 0.0729
tanθ = 3.7

Verifying it lies in the range

θ = tan⁻¹ (3.7)
θ = 74.88°
Range is : 0 < θ < π/2 [or 0 < θ < 90°]
It lies in the range [Verified]

7 0

2 years ago

Write the expression for when you translate the graph of y = | 1/2 x−2 |+3 a) one unit up, b) one unit down, c) one unit to the

alukav5142 [94]

Answer:

a) y = |x/2 -2| +4

b) y = |x/2 -2| +2

c) y = |(x+1)/2 -2| +3

d) y = |(x-1)/2 -2| +3

Step-by-step explanation:

To translate the function f(x) by (h, k) in the (right, up) direction, you transform it to ...

g(x) = f(x -h) +k

a) one unit up

Add 1 to the function value.

$y=\left|\dfrac{x}{2}-2\right|+3+1\\\\\boxed{y=\left|\dfrac{x}{2}-2\right|+4}$

b) one unit down

Subtract 1 from the function value.

$y=\left|\dfrac{x}{2}-2\right|+3-1\\\\\boxed{y=\left|\dfrac{x}{2}-2\right|+2}$

c) one unit left

Replace x with x-(-1).

$y=\left|\dfrac{x-(-1)}{2}-2\right|+3\\\\\boxed{y=\left|\dfrac{x+1}{2}-2\right|+3}$

d) one unit right

Replace x with x-1.

$\boxed{y=\left|\dfrac{x-1}{2}-2\right|+3}$

7 0

3 years ago

Point M is located at (-2,7). If point N is 10 units away from point M, how many possible cordinate pairs

natulia [17]

Answer:

2 possible coordinate pairs

N (8, 17) OR (-12, -3)

Step-by-step explanation:

The rule:

(x, y) => (x + 10, y + 10) OR (x - 10, y -10)

(-2 + 10, 7 + 10) OR (-2 - 10, 7 -10)

(8, 17) OR (-12, -3)

Hope this helps!

6 0

3 years ago

How do I round 35.26 to the nearest whole number

Masja [62]

The rounded number to nearest whole number of 35.26 will be 35.

This is because we consider lower limit if the decimal is lower than 5, and consider the upper limit when the decimal is greater than 5.

7 0

4 years ago

Solve using completing the square x^2 – 8x + 16 = 25

lisov135 [29]

First we need to factor the left side. Since it is a perfect square (as is the process with completing the square, we know we can take half of the middle number along with x to be in the two parenthesis.

(x - 4)(x - 4) = 25

Now we simplify to show it as a square.

(x - 4)^2 = 25

Next we take the square root of both sides

x - 4 = +/- 5

Note that we have plus or minus 5. This is because either square would give us positive 25. Now we add 4 to both sides

x = 4 +/- 5

4 + 5 = 9

4 - 5 = -1

5 0

3 years ago