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cluponka [151]
3 years ago
7

How many ounces of 10% alcohol would need to be mixed with pure rubbing alcohol to get 16

Mathematics
1 answer:
givi [52]3 years ago
6 0

Suppose you add <em>x</em> oz of 10% alcohol to <em>y</em> oz of pure alcohol. Then the mixture has a total volume of <em>x</em> + <em>y</em> oz, and we want to end up with 16 oz so that

<em>x</em> + <em>y</em> = 16

For each oz of the solution 10% used, 0.1 oz of alcohol is contributed, and each oz of pure alcohol contributes 1 oz of alcohol. The mixture is supposed to have a concentration of 14%, which comes out to 0.14*16 = 2.24 oz of alcohol. Then

0.1<em> x</em> + 1 <em>y</em> = 2.24

Solve for <em>y</em> in both equations:

<em>y</em> = 16 - <em>x</em>

<em>y</em> = 2.24 - 0.1 <em>x</em>

Set them equal to one another and solve for <em>x</em>, then for <em>y</em>.

16 - <em>x</em> = 2.24 - 0.1 <em>x</em>

13.76 = 0.9 <em>x</em>

<em>x</em> = 13.76/0.9 ≈ 15.29

<em>y</em> = 16 - 15.29 ≈ 0.71

So you need about 15.29 oz of 10% alcohol and 0.71 oz of pure alcohol to get the desired mixture.

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