Could someone help and tell me how you got the answer? Will mark brainlist!

Mathematics

2 answers:

zheka24 [161]2 years ago

8 0

Subtract 2 numbers then subtract it with 180 (sorry if you get it wrong)

crimeas [40]2 years ago

4 0

This answer is 8 make brainly

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Reduce fractions expressing probability to lowest terms.

igomit [66]

Answer:

The expected probability is 1 over 6

So ,Your answer is : 1/6

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3 years ago

What is the discriminant of the quadratic equation 0 = 2x2 3x – 5?

a_sh-v [17]

If you would like to find the discriminant of the quadratic equation 0 = 2x^2 + 3x - 5, you can do this using the following steps:

0 = 2x^2 + 3x - 5
0 = ax^2 + bx + c
a = 2, b = 3, c = - 5

D = b^2 - 4 * a * c = 3^2 - 4 * 2 * (-5) = 9 + 40 = 49

The correct result would be 49.

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3 years ago

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Pls help on math hw for algebra

DiKsa [7]

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2 years ago

Help with Geometry needed! For this figure, what is the value of X?

Finger [1]

Hello! A triangle has angles that sum up to 180°. So first off, let's solve for the angle of the other triangle. 83 + 31 gives us 114. 180 - 114 is 66. So the angle for the first triangle is 66°. The opposite angle would be the same. Finding the measurement of the other triangle gives us the measurement of x, because the angles are the same. So x = 66°.

3 0

2 years ago

The vertices of ∆ABC are A(2, 8), B(16, 2), and C(6, 2). what is the perimeter and area in square units

ad-work [718]

Check the picture below.

the triangle has that base and that height, recall that A = 1/2 bh.

now as for the perimeter, you can pretty much count the units off the grid for the segment CB, so let's just find the lengths of AC and AB,

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&A&(~ 2 &,& 8~) 
% (c,d)
&C&(~ 6 &,& 2~)
\end{array}~~~ 
% distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
AC=\sqrt{(6-2)^2+(2-8)^2}\implies AC=\sqrt{4^2+(-6)^2}
\\\\\\
AC=\sqrt{16+36}\implies AC=\sqrt{52}\implies AC=\sqrt{4\cdot 13}
\\\\\\
AC=\sqrt{2^2\cdot 13}\implies AC=2\sqrt{13}$

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&A&(~ 2 &,& 8~) 
% (c,d)
&B&(~ 16 &,& 2~)
\end{array}\\\\\\
AB=\sqrt{(16-2)^2+(2-8)^2}\implies AB=\sqrt{14^2+(-6)^2}
\\\\\\
AB=\sqrt{196+36}\implies AB=\sqrt{232}\implies AB=\sqrt{4\cdot 58}
\\\\\\
AB=\sqrt{2^2\cdot 58}\implies AB=2\sqrt{58}$

so, add AC + AB + CB, and that's the perimeter of the triangle.

8 0

3 years ago