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Harman [31]
3 years ago
5

Identify the products of a reaction under kinetic control. a. The most stable product. b. The product whose formation requires t

he smallest free energy of activation. c. The product that can be formed in the fewest steps. d. The product that is formed at the fastest rate. e. None of these.
Chemistry
1 answer:
aleksley [76]3 years ago
3 0

Answer: Option (b) and (d) are the correct answer.

Explanation:

Kinetic products are defined as the products which contain a terminal double bond and the reaction is irreversible in nature.

Kinetic controlled products are formed faster because these tend to lower the activation energy. Due to this molecules with less energy are also able to participate in the reaction.

Therefore, rate of reaction increases leading to rapid formation of products.

Therefore, we can conclude that the products of a reaction under kinetic control are product that is formed at the fastest rate and product whose formation requires the smallest free energy of activation.

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What is maximum mass of carbohydrate in a 6-oz serving of diet soda that contains less than 1 Calorie per can if the average num
masya89 [10]

Answer:

0.24 g

Explanation:

Given that:

The average number of the calories for the carbohydrates = 4.1 calorie / g

Also,

6 - oz serving of the diet soda contains less than 1 calorie per can

So,

Maximum mass of carbohydrate = Maximum calorie / Average number of the calories for the carbohydrates

The maximum of the calorie can be 1 calorie per can

So,

<u>Maximum mass of carbohydrate = 1 calorie / 4.1 calorie / g = 0.24 g</u>

3 0
3 years ago
The equation represents the combustion of sucrose. C12H22O11 + 12O2 12CO2 + 11H2O If there are 10.0 g of sucrose and 8.0 g of ox
Vaselesa [24]
<span>0.0292 moles of sucrose are available. First, lookup the atomic weights of all involved elements Atomic weight Carbon = 12.0107 Atomic weight Hydrogen = 1.00794 Atomic weight Oxygen = 15.999 Now calculate the molar mass of sucrose 12 * 12.0107 + 22 * 1.00794 + 11 * 15.999 = 342.29208 g/mol Divide the mass of sucrose by its molar mass 10.0 g / 342.29208 g/mol = 0.029214816 mol Finally, round the result to 3 significant figures, giving 0.0292 moles</span>
7 0
3 years ago
HELPP!!
ikadub [295]

Answer: C. CO₂ and H₂O

Explanation:

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3 0
2 years ago
A chemist fills a reaction vessel with 0.750 M lead (II) (Pb2+) aqueous solution, 0.232 M bromide (Br) aqueous solution, and 0.9
Ronch [10]

Answer:

The free energy = -20.46 KJ

Explanation:

given Data:

Pb²⁺ = 0.750 M

Br⁻ = 0.232 M

R = 8.314 Jk⁻¹mol⁻¹

T = 298K

The Gibb's free energy is calculated using the formula;

ΔG = ΔG° + RTlnQ -------------------------1

Where;

ΔG° = standard Gibb's freeenergy

R = Gas constant

Q = reaction quotient

T = temperature

The chemical reaction is given as;

Pb²⁺(aq) + 2Br⁻(aq) ⇄PbBr₂(s)

The ΔG°f are given as:

ΔG°f (PbBr₂)  = -260.75 kj.mol⁻¹

ΔG°f (Pb²⁺)   = -24.4 kj.mol⁻¹

ΔG°f (2Br⁻)    = -103.97 kj.mol⁻¹

Calculating the standard gibb's free energy using the formula;

ΔG° = ξnpΔG°(product) - ξnrΔG°(reactant)

Substituting, we have;

ΔG° =[1mol*ΔG°f (PbBr₂)] - [1 mol *ΔG°f (Pb²⁺) +2mol *ΔG°f (2Br⁻)]

ΔG° =(1 *-260.75 kj.mol⁻¹) - (1* -24.4 kj.mol⁻¹) +(2*-103.97 kj.mol⁻¹)

      = -260.75 + 232.34

     = -28.41 kj

Calculating the reaction quotient Q using the formula;

Q = 1/[Pb²⁺ *(Br⁻)²]

   = 1/(0.750 * 0.232²)

  = 24.77

Substituting all the calculated values into equation 1, we have

ΔG = ΔG° + RTlnQ

ΔG = -28.41 + (8.414*10⁻³ * 298 * In 24.77)

     = -28.41 +7.95

    = -20. 46 kJ

Therefore, the free energy of reaction = -20.46 kJ

8 0
3 years ago
Metals experience plastic deformation when _____.
xxTIMURxx [149]

Metals experience plastic deformation when a specific amount of pressure and temperature is applied to them. Most metals have low specific heat. Because of their low specific heat, they easily get hot when heat is applied to them.

3 0
3 years ago
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