Answer:
6.68 X 10^-11
Explanation:
From the second Ka, you can calculate pKa = -log (Ka2) = 6.187
The pH at the second equivalence point (8.181) will be the average of pKa2 and pKa3. So,
8.181 = (6.187 + pKa3) / 2
Solving gives pKa3 = 10.175, and Ka3 = 10^-pKa3 = 6.68 X 10^-11
Phase 3 is the integration phrase
Answer : 50.69 mg of ascorbic acid does not meet the daily requirement.
Solution : Given,
Molar mass of Ascorbic acid = 176 g/mole
Moles of Ascorbic acid = 
Formula used :

or, 
Now put all the given values in this formula, we get the mass of ascorbic acid.

Conversion : 
As per question, a healthy adult’s daily requirement of vitamin C is 70-90 mg. But calculate mass of vitamin C is 50.69 mg. So, 50.69 mg of ascorbic acid does not meet the daily requirement.
Answer:
They propagate in materialistic media and non-materialistic media ( space ) .
They propagate in the space at constant velocity , which is 3 × 108 m/s .
They consist of vibrating electric and magnetic fields at certain frequency in phase with each other , perpendicular to each other and perpendicular to the direction of the wave propagation ...
Explanation:
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