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ANTONII [103]
3 years ago
10

The equation represents the combustion of sucrose. C12H22O11 + 12O2 12CO2 + 11H2O If there are 10.0 g of sucrose and 8.0 g of ox

ygen, how many moles of sucrose are available for this reaction?
Chemistry
1 answer:
Vaselesa [24]3 years ago
7 0
<span>0.0292 moles of sucrose are available. First, lookup the atomic weights of all involved elements Atomic weight Carbon = 12.0107 Atomic weight Hydrogen = 1.00794 Atomic weight Oxygen = 15.999 Now calculate the molar mass of sucrose 12 * 12.0107 + 22 * 1.00794 + 11 * 15.999 = 342.29208 g/mol Divide the mass of sucrose by its molar mass 10.0 g / 342.29208 g/mol = 0.029214816 mol Finally, round the result to 3 significant figures, giving 0.0292 moles</span>
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Arrange the following types of photons of electromagnetic radiation in order of decreasing energy: red light, radio, x-rays, γ-r
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Decreasing order is as follows:

γ-rays > x-rays > red light > infrared > radio

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The Following questions pertain to a 2.2M solution of hydrocyanic acid at 25°C. pKa = 9.21 at 25°C. Find the concentrations of a
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1) Chemical reaction: HCN + H₂O → CN⁻ + H₃O⁺.
c(HCN) = 2,2 M = 2,2 mol/L.
pKa(HCN) = 9,21.
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[CN⁻] = [H₃O⁺] = x.
[HCN<span>] = 2,2 M - x.
</span>Ka = [CN⁻] · [H₃O⁺] / [HCN].
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2) pH = - log[H₃O⁺].
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pH = 4,46.
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pKb = pKw - pKa.
pKb = 14 - 9,21 = 4,79.

6 0
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