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ANTONII [103]
3 years ago
10

The equation represents the combustion of sucrose. C12H22O11 + 12O2 12CO2 + 11H2O If there are 10.0 g of sucrose and 8.0 g of ox

ygen, how many moles of sucrose are available for this reaction?
Chemistry
1 answer:
Vaselesa [24]3 years ago
7 0
<span>0.0292 moles of sucrose are available. First, lookup the atomic weights of all involved elements Atomic weight Carbon = 12.0107 Atomic weight Hydrogen = 1.00794 Atomic weight Oxygen = 15.999 Now calculate the molar mass of sucrose 12 * 12.0107 + 22 * 1.00794 + 11 * 15.999 = 342.29208 g/mol Divide the mass of sucrose by its molar mass 10.0 g / 342.29208 g/mol = 0.029214816 mol Finally, round the result to 3 significant figures, giving 0.0292 moles</span>
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. Given the reaction 2HgO → 2Hg + O2 , how many moles of elemental mercury will be obtained by the decomposition of 1 mole of Hg
AveGali [126]

Answer:

one mole of HgO will give one mole of Hg.

Explanation:

Given data:

Moles of HgO = 1 mol

Moles of Hg = ?

Solution:

Chemical equation:

2HgO → 2Hg + O₂

Now we will compare the moles of Hg with HgO from balance chemical equation.

                  HgO   :     Hg

                    2       :      2

                     1       :      2/2×1 = 1 mol

So, one mole of HgO will give one mole of Hg.

6 0
3 years ago
Why is global warming called the greenhouse effect?
nika2105 [10]
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3 0
4 years ago
Which of the following steps in a star's life cycle takes the longest?
Vsevolod [243]
<span>The correct anwser is "C.fusion of hydrogen atoms"</span>
4 0
3 years ago
Once the ionic solid has dissolved, the anion that is formed is able to react as a base, with water as the acid. Write the net a
puteri [66]

Answer:

OCl− + H2O ⇌ HOCl + OH−

Explanation:

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3 0
3 years ago
How many ml of a 0.50m solution of hno3 solution are needed to make 500 ml of 0.15m hno3
Anna71 [15]

Answer:

150.0 mL.

Explanation:

  • It is known that the no. of millimoles of HNO₃ before dilution = the no. of millimoles of HNO₃ after dilution.

∵ (MV) before dilution = (MV) after dilution.

<em>∴ V before dilution = (MV) after dilution / M before dilution</em> = (0.15 M)(500.0 mL)/(0.50 M) = <em>150.0 mL.</em>

7 0
3 years ago
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