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Aleks [24]
2 years ago
15

HELPP!!

Chemistry
1 answer:
ikadub [295]2 years ago
3 0

Answer: C. CO₂ and H₂O

Explanation:

Combustion reactions produce carbon dioxide and water.

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Mass of CuSO4● XH2O (g) = 1.6 grams BEFORE HEATING
Leokris [45]

0.06105 moles is the number of moles of water lost.

<h3>What is molar mass?</h3>

Molar mass is defined as the mass in grams of one mole of a substance.

Given data:

Mass of water = 1.1g

Molar mass water = 18.016 g/mol

Moles of water =?

These quantities are related by the following equation;

Moles = \frac{Mass}{Molar \;mass}

Substituting the values of the quantities and solving for moles, we have;

Moles =  \frac{1.1 }{18.016} = 0.06105 moles.

Hence, the 0.06105 moles is the number of moles of water lost.

Learn more about molar mass here:

brainly.com/question/12127540

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7 0
2 years ago
As the concentration of a KOH solution increases, the number of moles of HCl needed to neutralize the KOH solution?
Soloha48 [4]

B) increasesAnswer:

Explanation:

8 0
2 years ago
A beaker is filled to the 500 mL mark with alcohol. What increase in volume (in mL) does the beaker contain when the temperature
Aliun [14]

Answer:

"1.4 mL" is the appropriate solution.

Explanation:

According to the question,

  • v_0=500
  • \alpha =1.12\times 10^{-4}
  • \Delta \epsilon = 25

Now,

Increase in volume will be:

⇒ \Delta V = \alpha\times v_0\times \Delta \epsilon

By putting the given values, we get

           =1.12\times 10^{-4}\times 500\times 25

           =1.12\times 10^{-4}\times 12500

           =1.4  \ mL

8 0
3 years ago
A particular reaction, A- products, has a rate that slows down as the reaction proceeds. The half-life of the reaction is found
Thepotemich [5.8K]

Explanation:

Half life of zero order and second order depends on the initial concentration. But as the given reaction slows down as the reaction proceeds, therefore, it must be second order reaction. This is because rate of reaction does not depend upon the initial concentration of the reactant.

a. As it is a second order reaction, therefore, doubling reactant concentration, will increase the rate of reaction 4 times. Therefore, the statement  a is wrong.

b. Expression for second order reaction is as follows:

\frac{1}{[A]} =\frac{1}{[A]_0} +kt

the above equation can be written in the form of Y = mx + C

so, the plot between 1/[A] and t is linear. So the statement b is true.

c.

Expression for half life is as follows:

t_{1/2}=\frac{1}{k[A]_0}

As half-life is inversely proportional to initial concentration, therefore, increase in concentration will decrease the half life. Therefore statement c is wrong.

d.

Plot between A and t is exponential, therefore there is no constant slope. Therefore, the statement d is wrong

8 0
3 years ago
Suppose that a certain fortunate person has a net worth of $77.0 billion ($). If her stock has a good year and gains $3.20 billi
marissa [1.9K]

Answer:

New net worth to three significant figures = $80.2 billion

Dollars are given to charity = $100,250,000

Explanation:

Net worth = $77.0 billion

stock Gains = $3.20 billion

New net worth = $77.0 billion + $3.20 billion = $80.20 billion

New net worth to three significant figures = $80.2 billion

One-eighth of a percent = (1/8 x 1) / 100 = 0.00125

Dollars are given to charity = 0.00125 X $80.2 billion = $100,250,000

Or

$80,200,000,000/100 = $802,000,000

3 0
3 years ago
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