Answer: Un alambre de acero de 1.5 m se estira 2.0 mm con fuerza F. El diámetro del alambre de acero es 4.0 mm. El módulo de Young del acero es 2.0 x 1011 Nm-2. Determine la fuerza F aplicada sobre el alambre.
Step-by-step explanation:
I would make a proportion out of this to help solve it because I find proportions a bit easier to solve, so the proportion would be: 110/100=880/x
You would just solve it for 800
l=51
m=78
n=51
n and l have the same value since it’s an isosceles triangle, so that’s why I doubled 4x-9
Answer:
ma ma ھگدفسخ टगाई samje ke hamreبھا मे
hoho gana ga